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Eva8 [605]
3 years ago
9

You roll a six-sided die one time. After that, you spin a spinner that is equally divided into 6 parts. 2 parts are red, 1 part

is pink and 3 parts are white. What is the probability of rolling a number greater than 1 and then the spinner stopping at a pink section?
Mathematics
1 answer:
Tanzania [10]3 years ago
3 0

Answer:

<h2>5/36</h2>

Step-by-step explanation:

This is a probability problem, so let us treat it as such.

the sample space for the die is =(1,2,3,4,5,6)

the sample size is =6

For the spinner the sample space is

red=2

pink=1

white=3

the sample size for the spinner is =6

The probability of rolling a number greater than 1 and then the spinner stopping at a pink section

=Pr(no>1)*Pr(spinner=pink)

no>1= 2,3,4,5,6

no>1=5

pink=1

hence

=5/6*1/6

=5/36

<h2>The probability is 5/36</h2>
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