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babunello [35]
3 years ago
8

Can someone help me so i can do the rest like this on my own/

Mathematics
1 answer:
stepladder [879]3 years ago
5 0
-- XY is a "diameter" of the circle. 

-- A diameter is any straight line inside the circle that goes
through the center and touches the curvy part twice.

-- Every diameter of the same circle has the same length.

-- The distance around every circle is (its diameter) multiplied by (pi).


-- Half of the diameter is called the "radius" of the circle.
A radius is any straight line inside the circle that goes between
the center and the curvy part.

-- The area of every circle is  (its radius, squared) times (pi).

-- 'Pi'  ( π )  is a number.  It's a decimal that keeps going forever
and never ends, so you can never write it exactly with numbers.

-- Pi is roughly 3.14 , and if you use 3.14 whenever you need pi,
then your answers will be about  0.05%  too small. 

That's very close.  When you turn in an answer that's only
0.05% wrong, the teacher knows that you know how to solve
the problem, and that's way more important than the answer.  

For the circle in your picture, the diameter is 17in, the radius
is 8.5in, and the area must be  (pi) (8.5)² square inches.
You can go ahead and work that out.
You might be interested in
BRAINLIEST
9966 [12]

Answer:

y+1=(x+7)/3

Step-by-step explanation:

slope = (-1-3)/(-7-5) = -4/-12 = 1/3

b = 3-(1/3)×5 = 4/3

y = mx+b

or, y = x/3+4/3

its point slope form,

y = x/3+4/3

or, y=(x+4)/3

or, y+1=(x+4)/3+1

or, y+1=(x+4+3)/7

or, y+1 =(x+7)/3

7 0
2 years ago
Will get brainliest!!!!!! Need by today!!!!!! please
Dovator [93]

Answer:

Step-by-step explanation:

dont know mate

8 0
3 years ago
Math question #1 please show steps
-Dominant- [34]

Answer:

C

Step-by-step explanation:

An approximation of an integral is given by:

\displaystyle \int_a^bf(x)\, dx\approx \sum_{k=1}^nf(x_k)\Delta x\text{ where } \Delta x=\frac{b-a}{n}

First, find Δx. Our a = 2 and b = 8:

\displaystyle \Delta x=\frac{8-2}{n}=\frac{6}{n}

The left endpoint is modeled with:

x_k=a+\Delta x(k-1)

And the right endpoint is modeled with:

x_k=a+\Delta xk

Since we are using a Left Riemann Sum, we will use the first equation.

Our function is:

f(x)=\cos(x^2)

Therefore:

f(x_k)=\cos((a+\Delta x(k-1))^2)

By substitution:

\displaystyle f(x_k)=\cos((2+\frac{6}{n}(k-1))^2)

Putting it all together:

\displaystyle \int_2^8\cos(x^2)\, dx\approx \sum_{k=1}^{n}\Big(\cos((2+\frac{6}{n}(k-1))^2)\Big)\frac{6}{n}

Thus, our answer is C.

*Note: Not sure why they placed the exponent outside the cosine. Perhaps it was a typo. But C will most likely be the correct answer regardless.

5 0
3 years ago
The given line passes through the points (0, −3) and (2, 3).
Alex Ar [27]
Well, parallel lines have the same exact slope, so hmmm what's the slope of the one that runs through <span>(0, −3) and (2, 3)?

</span>\bf \begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&&(~ 0 &,& -3~) &#10;%  (c,d)&#10;&&(~ 2 &,& 3~)&#10;\end{array}&#10;\\\\\\&#10;% slope  = m&#10;slope =  m\implies &#10;\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{3-(-3)}{2-0}\implies \cfrac{3+3}{2-0}\implies 3
<span>
so, we're really looking for a line whose slope is 3, and runs through -1, -1

</span>\bf \begin{array}{ccccccccc}&#10;&&x_1&&y_1\\&#10;%  (a,b)&#10;&&(~ -1 &,& -1~)&#10;\end{array}&#10;\\\\\\&#10;% slope  = m&#10;slope =  m\implies 3&#10;\\\\\\&#10;% point-slope intercept&#10;\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-1)=3[x-(-1)]&#10;\\\\\\&#10;y+1=3(x+1)<span>
</span>
8 0
3 years ago
Read 2 more answers
If cos theta=-3/5 in quadrant 2 what is sin theta?<br><br> A:4/5<br> B:3/4<br> C:-3/4<br> D:-4/5
Scrat [10]
Answer: Choice A) 4/5

-------------------------------------------

Work Shown:

cos^2(theta) + sin^2(theta) = 1
(-3/5)^2 + sin^2(theta) = 1
9/25 + sin^2(theta) = 1
9/25 + sin^2(theta) - 9/25 = 1 - 9/25
sin^2(theta) = 1 - 9/25
sin^2(theta) = 25/25 - 9/25
sin^2(theta) = (25 - 9)/25
sin^2(theta) = 16/25
sqrt[sin^2(theta)] = sqrt[16/25]
sin(theta) = 4/5

The fact that sine is positive in quadrant 2 means that the result is positive.
8 0
3 years ago
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