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SIZIF [17.4K]
3 years ago
15

PLEASE HELP!! WILL MARK BRAINLIEST!

Mathematics
1 answer:
Tasya [4]3 years ago
5 0

Answer:

i think its gay

Step-by-step explanation:

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Step-by-step explanation:

Using slope formula m = rise/run

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If 223x=78,find x. If 223x=78, find x
Maslowich

Answer:0.3273542601

Step-by-step explanation:

73÷223=0.3273542601

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What percent of 82.5 is 21.12
Travka [436]
<span>21.12 is 25.6% of 82.5</span>

hope this helps!! :)
have a good day!! :D
plz mark brainliest!! XD
8 0
4 years ago
Read 2 more answers
Two candidates face each other in an election. The Democratic candidate is supported by 46% of the population, and the Republica
7nadin3 [17]

Answer:

27.98% probability that less than half of them (3 or fewer) would support the Republican candidate

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they support the Republican candidate, or they do not. The people are chosen at random, which means that the probability of them supporting the republican candidate is independent from other people. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

The Republican candidate is supported by 54%. This means that p = 0.54

Suppose you run a poll of 8 people (randomly choose 8 people). What is the probability that less than half of them (3 or fewer) would support the Republican candidate?

This is P(X \leq 3) when n = 8.

So

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{8,0}.(0.54)^{0}.(0.46)^{8} = 0.0020

P(X = 1) = C_{8,1}.(0.54)^{1}.(0.46)^{7} = 0.0188

P(X = 2) = C_{8,2}.(0.54)^{2}.(0.46)^{6} = 0.0774

P(X = 3) = C_{8,3}.(0.54)^{3}.(0.46)^{5} = 0.1816

So

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0020 + 0.0188 + 0.0774 + 0.1816 = 0.2798

27.98% probability that less than half of them (3 or fewer) would support the Republican candidate

3 0
3 years ago
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