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Elodia [21]
3 years ago
10

WHATS THE SLOPE? I need this ASAP!!

Mathematics
1 answer:
evablogger [386]3 years ago
4 0
The answer to this is 4/3
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What is 149x1007? because i am having troubles trying to figure out
solniwko [45]

Answer:

150043 Is the answer

6 0
3 years ago
You get GPS units from two manufacturers, A and B. You get 43% of your units from A and 57% of your units from B. In the past, 2
defon

Answer:

0.5015 = 50.15% probability that it came from manufacturer A.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Defective

Event B: From manufacturer A.

Probability a unit is defective:

2% of 43%(from manufacturer A)

1.5% of 57%(from manufacturer B). So

P(A) = 0.02*0.43 + 0.015*0.57 = 0.01715

Probability a unit is defective and from manufacturer A:

2% of 43%. So

P(A \cap B) = 0.02*0.43 = 0.0086

What is the probability that it came from manufacturer A?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0086}{0.01715} = 0.5015

0.5015 = 50.15% probability that it came from manufacturer A.

4 0
3 years ago
Multiply. 0.72*10^2=
velikii [3]

Answer: The Answer is 72 or 7.2x10^1

This is due to 10^2 equaling 100. 100x0.72 is 72 bec you are moving the decimal point 2 to the right.

8 0
3 years ago
PLEEASSEEEE Answer ASAP. Due in 5 Minutes. 25 points!!!!!!!!!
jonny [76]

Answer:

Here we will use the relationships:

a^n*a^m = a^{n + m}

(a^n)^m = a^{n*m}

\frac{a^n}{a^m} = a^{n - m}

And a number:

a^n

is between 0 and 1 if a is positive and larger than 1, and n is negative.

if a is positive and 0 < a < 1, then we need to have n positive such that:

0 < a^n < 1

A) 5^3*5^{-4} = 5^{3 + (-4)} = 5^{-1}

This is between zero and 1,

B) \frac{3^5}{3^{-6}} = 3^{5 - (-6)} = 3^{11}

This is greater than 1, because the exponent is positive.

C) (\frac{1}{4})^3*( \frac{1}{4})^2 = (\frac{1}{4})^{2 + 3} = (\frac{1}{4})^5

Because a is smaller than 1, and the exponent is positive, then the expression is between 0 and 1.

D) \frac{(-7)^5}{(-7)^7} = (-7)^{5 - 7} = -7^{-2}

The exponent is negative (and pair) then the expression is between 0 and 1.

Remember that when the exponent is pair, we always have that:

(-N)^m = (N)^m

So (-7)^-2 = 7^-2

4 0
3 years ago
Help with 4 and 6<br> And is 5 correct?
Neporo4naja [7]

Answer:

4) 0, -1, 1, 1, 1

5) correct

6) x = -2 \pm 2\sqrt5

Step-by-step explanation:

4) fill in the previous sequence element in the next. This sequence gets "stuck" at 1.

6) use the quadratic formula.

8 0
4 years ago
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