We know that
The inscribed angle Theorem states that t<span>he inscribed angle measures half of the arc it comprises.
</span>so
m∠D=(1/2)*[arc EFG]
and
m∠F=(1/2)*[arc GDE]
arc EFG+arc GDE=360°-------> full circle
applying multiplication property of equality
(1/2)*arc EFG+(1/2)*arc GDE=180°
applying substitution property of equality
m∠D=(1/2)*[arc EFG]
m∠F=(1/2)*[arc GDE]
(1/2)*arc EFG+(1/2)*arc GDE=180°----> m∠D+m∠F=180°
the answer in the attached figure
Answer:
The volume of a rectangular prism is simply the product of its three dimensions: in your case, the volume of the prism is, given
x
,
(
x
+
6
)
(
x
−
2
)
(
x
−
1
)
.
A polynomial is a sum (with some coefficients) of powers of
x
, so, if we expand the product just written, we have
(
(
x
+
6
)
(
x
−
2
)
)
(
x
−
1
)
=
(
x
2
−
2
x
+
6
x
−
12
)
(
x
−
1
)
=
(
x
2
+
4
x
−
12
)
(
x
−
1
)
=
x
3
+
4
x
2
−
12
x
−
x
2
−
4
x
+
12
=
x
3
+
3
x
2
−
16
x
+
12
Which is a polynomial, and expresses the volume of the prism
Step-by-step explanation:
The volume of a rectangular prism is simply the product of its three dimensions: in your case, the volume of the prism is, given
x
,
(
x
+
6
)
(
x
−
2
)
(
x
−
1
)
.
A polynomial is a sum (with some coefficients) of powers of
x
, so, if we expand the product just written, we have
(
(
x
+
6
)
(
x
−
2
)
)
(
x
−
1
)
=
(
x
2
−
2
x
+
6
x
−
12
)
(
x
−
1
)
=
(
x
2
+
4
x
−
12
)
(
x
−
1
)
=
x
3
+
4
x
2
−
12
x
−
x
2
−
4
x
+
12
=
x
3
+
3
x
2
−
16
x
+
12
Which is a polynomial, and expresses the volume of the prism
Here are three ratios
1 6/7
2 120/140
3 60/70
A "solution" would be a set of three numbers ... for Q, a, and c ... that
would make the equation a true statement.
If you only have one equation, then there are an infinite number of triplets
that could do it. For example, with the single equation in this question,
(Q, a, c) could be (13, 1, 2) and they could also be (16, 2, 1).
There are infinite possibilities with one equation.
In order to have a unique solution ... three definite numbers for Q, a, and c ...
you would need three equations.