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oksian1 [2.3K]
2 years ago
5

I need help, can you help me?​

Mathematics
2 answers:
Aneli [31]2 years ago
5 0

Answer:

with what? I can try

Step-by-step explanation:

(◍•ᴗ•◍)✿

GREYUIT [131]2 years ago
3 0

depends....

whats the problem or question?

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What is 17x^2=12x in general quadratic form
ZanzabumX [31]
<span>Simplifying 17x2 + -12x = 0 Reorder the terms: -12x + 17x2 = 0 Solving -12x + 17x2 = 0 Solving for variable 'x'. Factor out the Greatest Common Factor (GCF), 'x'. x(-12 + 17x) = 0 </span>
7 0
3 years ago
The length of a rectangle is 3 inches more than the width. The area is 10 square inches. Find the dimensions
mr_godi [17]

Answer:

Width = 2

Length = 5

Step-by-step explanation:

let A be the area of the rectangle

   L be the length of the rectangle

   w be the width of the rectangle

<u><em>Formula</em></u>: ‘<u><em>area of a rectangle</em></u>’

A = L × w

…………………………………………………

A = L × w

⇔ 10 = (w + 3) × w

⇔ 10 = w² + 3w

⇔ w² + 3w - 10 = 0  

<u><em>Solving the quadratic equation</em></u> w² + 3w - 10 =  0 :

Δ = 3² - 4(1)(-10) = 9 - (-40) = 9 + 40 = 49

then √Δ = 7

\Longrightarrow w=\frac{-b+\sqrt{\Delta } }{2a} =\frac{-3+7}{2} =2

  or\ w=\frac{-b-\sqrt{\Delta } }{2a} =\frac{-3-7}{2} =-5

-5 is not valid ,because w represents the width

which must be a positive number

Then  w = 2

<u><em>Conclusion</em></u>:

Width = 2

Length = 2 + 3 = 5

6 0
2 years ago
Which of the following best describes an Extraneous Solution?
miv72 [106K]

Answer:

An extraneous solution is a solution obtained through algebraic manipulations that is not a solution to the original equation.

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
a runner is 7/8 mile from the finsh line. she can travel 3/8 mile per minute,how long will it take her to finsh the race
Simora [160]
I hope this helps you

if 3/8 miles per a hour

7/8 miles ? hour

?.3/8=7/8.1

?=7/3

?=2,3333... hour
4 0
3 years ago
In going to the store, you walked 1⁄6 of a mile but on the way back, you took the path through the park and walk 1⁄3 of a mile.
dsp73
This reduces to a simple addition problem.

You walk 1/6 or one sixth of a mile, then 1/3 or one third of a mile.

The result is 1/3 + 1/6.
Using basic properties of fractions, we can substitute 2/6 for 1/3:
2/6 + 1/6 = 3/6.
3/6 is three sixths, which is exactly 1/2.

So in total, you walked 1/2 miles.
6 0
3 years ago
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