Just had a total brain fart, no idea how to answer this
2 answers:
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Using the z-distribution, it is found that the 95% confidence interval is (0.46, 0.526), and it does not provide strong evidence against that belief.
<h3>What is a confidence interval of proportions?</h3>A confidence interval of proportions is given by:
In which:
is the sample proportion.
- z is the critical value.
- n is the sample size.
In this problem, we have a 95% confidence level, hence, z is the value of Z that has a p-value of
, so the critical value is z = 1.96.
We have that a random sample of 864 births in a state included 426 boys, hence the parameters are given by:
Then, the bounds of the interval are given by:
The 95% confidence interval estimate of the proportion of boys in all births is (0.46, 0.526). Since the interval contains 0.506, it does not provide strong evidence against that belief.
More can be learned about the z-distribution at brainly.com/question/25890103
ANSWER
EXPLANATION
The given equation is
Divide both sides by
Cancel out common factors on the left hand side,
For this solution to be a whole number, then should be a factor of
.
The reason is that, factors of 6 will divide exactly in to 6 without a remainder, making the answer a whole number.
The whole numbers that are factors of 6 are,
Note that, the set of whole numbers are,
{
}
EXPLANATION
The given equation is
Divide both sides by
Cancel out common factors on the left hand side,
For this solution to be a whole number, then
The reason is that, factors of 6 will divide exactly in to 6 without a remainder, making the answer a whole number.
The whole numbers that are factors of 6 are,
Note that, the set of whole numbers are,
{