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uranmaximum [27]
3 years ago
10

Talk Room

Computers and Technology
2 answers:
Lena [83]3 years ago
6 0

Answer:

i m here to get points.........................................................................................................

Explanation:

Paraphin [41]3 years ago
3 0

hey ,how are you my dude?:)

You might be interested in
I put 100 points in here
tatuchka [14]

Answer:

you only put 50 points not 100

4 0
3 years ago
Design a class called NumDays. The class’s purpose is to store a value that represents a number of work hours and convert it to
stepladder [879]

Answer:

See explaination

Explanation:

#include <iostream>

using namespace std;

class NumDays{

int hours;

float day;

public:

NumDays()

{

hours=0;

day=0.0;

};

NumDays(int h)

{

hours=h;

day=float(h/8.0);

};

int getHour()

{

return hours;

}

float getDay()

{

return day;

}

NumDays operator +(NumDays obj)

{

int h=getHour()+obj.getHour();

NumDays temp(h);

return temp;

}

NumDays operator -(NumDays obj)

{

int h=getHour()-obj.getHour();

NumDays temp(h);

return temp;

}

const NumDays& operator++() //prefix

{

++hours;

day=float(hours/8.0);

return *this;

}

const NumDays& operator--() //prefix

{

--hours;

day=float(hours/8.0);

return *this;

}

const NumDays operator++(int) //postfix

{

NumDays temp(*this);

++hours;

day=float(hours/8.0);

return temp;

}

const NumDays operator--(int) //postfix

{

NumDays temp(*this);

--hours;

day=float(hours/8.0);

return temp;

}

};

int main()

{

NumDays obj(2),obj2(10),obj3,obj4;

obj3=obj2-obj;

cout<<"'obj3=obj2-obj'=> Day:"<<obj3.getDay()<<"##Hour:"<<obj3.getHour()<<"\n";

obj3=obj+obj2;

cout<<"'obj3=obj+obj2'=> Day:"<<obj3.getDay()<<"##Hour:"<<obj3.getHour()<<"\n";

obj4=obj3++;

cout<<"'obj4=obj3++' => Day:"<<obj4.getDay()<<"##Hour:"<<obj4.getHour()<<"\n";

obj4=++obj3;

cout<<"'obj4=++obj3' => Day:"<<obj4.getDay()<<"##Hour:"<<obj4.getHour()<<"\n";

obj4=obj3--;

cout<<"'obj4=obj3--' => Day:"<<obj4.getDay()<<"##Hour:"<<obj4.getHour()<<"\n";

obj4=--obj3;

cout<<"'obj4=--obj3' => Day:"<<obj4.getDay()<<"##Hour:"<<obj4.getHour()<<"\n";

};

3 0
3 years ago
Write a method that accepts a String object as an argument and returns a copy of the string with the first character of each sen
emmainna [20.7K]

Answer:

The programming language is not stated; However, the program written in C++ is as follows: (See Attachment)

#include<iostream>

using namespace std;

string capt(string result)

{

result[0] = toupper(result[0]);

for(int i =0;i<result.length();i++){

 if(result[i]=='.' || result[i]=='?' ||result[i]=='!')  {

 if(result[i+1]==' ') {

  result[i+2] = toupper(result[i+2]);

 }

 if(result[i+2]==' ')  {

  result[i+3] = toupper(result[i+3]);

 }

 } }

return result;

}

int main(){

string sentence;

getline(cin,sentence);

cout<<capt(sentence);

return 0;

}

Explanation:

<em>The method to capitalize first letters of string starts here</em>

string capt(string result){

<em>This line capitalizes the first letter of the sentence</em>

result[0] = toupper(result[0]);

<em>This iteration iterates through each letter of the input sentence</em>

for(int i =0;i<result.length();i++){

This checks if the current character is a period (.), a question mark (?) or an exclamation mark (!)

if(result[i]=='.' || result[i]=='?' ||result[i]=='!')  {

 if(result[i+1]==' '){  ->This condition checks if the sentence is single spaced

  result[i+2] = toupper(result[i+2]);

-> If both conditions are satisfied, a sentence is detected and the first letter is capitalized

 }

 if(result[i+2]==' '){ ->This condition checks if the sentence is double spaced

  result[i+3] = toupper(result[i+3]);

-> If both conditions are satisfied, a sentence is detected and the first letter is capitalized

 }

}

}  <em>The iteration ends here</em>

return result;  ->The new string is returned here.

}

The main method starts here

int main(){

This declares a string variable named sentence

string sentence;

This gets the user input

getline(cin,sentence);

This passes the input string to the method defined above

cout<<capt(sentence);

return 0;

}

Download cpp
7 0
4 years ago
. Describe a way to simplify a complex problem.
Inga [223]

Answer:

Simplify a complex problem means reduces its complexity and make it easy to understand. When we make the problem simplified then, the data become more clear and understandable.

There are many ways to simplify a complex problem as follows:

  • Organize the information and content properly and reduces the layers of complexity. Organized the content in the form of steps so that it become easy to understand.
  • Use of clear language is one of the most important part to make the content more clear and use proper formatting of the data.
  • Break the information into smaller parts to it can easy to read and looks more clearly. So, the reader finds it more comfortable and efficient.

5 0
3 years ago
Your ___________ is what you can see without the presence of an obstruction.
SCORPION-xisa [38]

Answer:

Line of sight

Explanation:

Your line of sight is the noticeable path of travel from your vehicle to your destination area. This line can be obstructed by a curve, a hill, high-forest wooded zones, large trucks, or other obstruction that prevents drivers from seeing the vehicle ahead. Therefore, if you cannot see around an obstruction, you should slow down and be willing to adjust your position until you can reestablish a clear line of sight to your path of travel and targeting area.

8 0
3 years ago
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