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Dovator [93]
3 years ago
8

. Describe a way to simplify a complex problem.

Computers and Technology
1 answer:
Inga [223]3 years ago
5 0

Answer:

Simplify a complex problem means reduces its complexity and make it easy to understand. When we make the problem simplified then, the data become more clear and understandable.

There are many ways to simplify a complex problem as follows:

  • Organize the information and content properly and reduces the layers of complexity. Organized the content in the form of steps so that it become easy to understand.
  • Use of clear language is one of the most important part to make the content more clear and use proper formatting of the data.
  • Break the information into smaller parts to it can easy to read and looks more clearly. So, the reader finds it more comfortable and efficient.

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2 years ago
Given two character strings s1 and s2. Write a Pthread program to find out the number of substrings, in string s1, that is exact
anyanavicka [17]

Answer:

Explanation:

#include <stdlib.h>

#include <stdio.h>

#include <string.h>

#define MAX 1024

int total = 0 ;

int n1, n2;

char s1, s2;

FILE fp;

int readf(FILE fp)

{

 if((fp=fopen("strings.txt", "r"))==NULL) {

   printf("ERROR: can’t open string.txt!\n");

   return 0;

 }

 s1=(char)malloc(sizeof(char)MAX);

 if(s1==NULL) {

   printf("ERROR: Out of memory!\n");

   return 1;

 }

 s2=(char)malloc(sizeof(char)MAX);

 if(s1==NULL) {

   printf("ERROR: Out of memory!\n");

   return 1;

 }

 /* read s1 s2 from the file */

 s1=fgets(s1, MAX, fp);

 s2=fgets(s2, MAX, fp);

 n1=strlen(s1); /* length of s1 */

 n2=strlen(s2)-1; /* length of s2 */

 if(s1==NULL || s2==NULL || n1<n2) /* when error exit */

   return 1;

}

int num_substring(void)

{

 int i, j, k;

 int count;

 for(i=0; i<=(n1-n2); i++) {

   count=0;

   for(j=i, k=0; k<n2; j++, k++){ /* search for the next string of size of n2 */

   if((s1+j)!=(s2+k)) {

     break;

   }

   else

     count++;

   if(count==n2)

     total++; /* find a substring in this step */

   }

 }

 return total;

}

int main(int argc, char argv[])

{

 int count;

 readf(fp);

 count=num_substring();

 printf("The number of substrings is: %d\n", count);

 return 1;

}

3 0
3 years ago
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