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NARA [144]
2 years ago
15

Anyone know what 8th grade workbook are these pages from called? Will give brainliest.

Mathematics
2 answers:
Hunter-Best [27]2 years ago
6 0

Step-by-step explanation:

PDF wont download so i cant see to tell you. sorry dont want yor points i have enough. give me some info if u can?

Angelina_Jolie [31]2 years ago
6 0

Answer: you have to go to tutoring

Step-by-step explanation: it not easy tho

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The number of cans the soup kitchen has is represented by the equation, y = -63x + 825, where x represents the number of days an
KiRa [710]
To find the answer to this question, we need to plug in x=10 into the equation y = -63x + 825.
y = -63(10) + 825
y = -630 + 825
y = 195
Thus, there will be 195 cans left after 10 days.
8 0
2 years ago
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The height (h) of a fireball launched from a Roman candle with an initial velocity of 64 feet per second is given by the equatio
Zigmanuir [339]

Answer: C or 2 seconds.

Step-by-step explanation:

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3 years ago
Susan needs to simplify the expression shown below.
mash [69]

Answer:

The answer to 75 - ( 8 + 45 ÷ 3 ) × 2= 29

3 0
2 years ago
A motorboat takes 5 hours to travel 100mi going upstream. The return trip takes 2 hours going downstream. What is the rate of th
Temka [501]
The boat went 5hours upstream, let's say it has a "still water" speed rate of "b", it went 100miles... however, going upstream is going against the current, let's say the current has a speed rate of "c"

so, when the boat was going up, it wasn't really going "b" fast, it was going " b - c " fast, because the current was eroding speed from it

now, when coming down, the return trip, well the length is the same, so the distance is also 100miles, it only took 2hrs though, because, the boat wasn't coming down  "b" fast, it was coming down " b + c " fast, because the current was adding speed to it, so it came down quicker

now, recall your d = rt, distance = rate * time

\bf \begin{array}{lccclll}
&distance&rate&time\\
&-----&-----&-----\\
upstream&100&b-c&5\\
downstream&100&b+c&2
\end{array}
\\\\\\
\begin{cases}
100=(b-c)5\\
\qquad \frac{100}{5}=b-c\\
\qquad 20=b-c\\
\qquad 20+c=\boxed{b}\\
100=(b+c)2\\
\qquad 50=b+c\\
\qquad 50=\boxed{20+c}+c
\end{cases}

solve for "c", to see what's the current's speed

what's "b"?  well 20+c = b
4 0
2 years ago
Maura drives to work, a distance of 30 miles in 40 minutes. she takes the same route to return home. if her average speed on the
Viefleur [7K]

Well to solve this firstly we should calculate her average speed while she was going to work. Which comes out to be 45 miles per hour.

Now if her average speed while going home is half as fast as while coming to work was, the answer would be 22.5 miles per hour. So the average speed for the total journey would be the average for these two values. As the distance was same for both the journeys we can simply do 45 + 22.5 / 2 = 33.75 mph.

8 0
3 years ago
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