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3 years ago

8. Chloe received $20.00 for her birthday. She

Mathematics

1 answer:

Leni [432]3 years ago

4 0

Answer: $9.23

because you multiply 3.59 by 3 to get $10.77 which was spent then you subtract $10.77 from $20.

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You want to count on to find 2 + 6. What number<br> would you start with? Why?

Nataliya [291]

Answer:

Step-by-step explanation:

It doesn't really matter but the equation is 2 + 6 not 6 + 2.

3 0

3 years ago

a taxi cab charges $4.25 for the first mile and$1.50 for each additional mile. what is the taxi rate for 12 miles

PtichkaEL [24]

$4.25 + $1.50 = $5.75= 2 miles
10 x $1.50 = $15.00=10 miles
10 + 2 = 12 miles
$5.75 + $15.00 = $20.75

4 0

3 years ago

An art exhibit is made by stacking three identical prisms on top of each other end-to-end so their smallest faces overlap. One o

cestrela7 [59]

The surface area of the exhibit is 1,638 cubic inches.

Step-by-step explanation:

Step 1:

If three prisms are out on top of each other we get a shape as follows;

The length of the base $= 9$ inches,

The width of the base $=6$ inches, and

The height of the exhibit $= 3(17) = 51$ inches.

To find the surface area of the total exhibit we consider there to be only one shape which the above dimension.

Step 2:

There are 6 faces to the exhibit.

The surface area of a rectangular prism is given by;

$A=2(w l+h l+h w)$

By substituting the values, we get

$A=2((6)(9)+(51) (9)+(51) (6)) = 2 (819) = 1,638.$

The surface area of the exhibit is 1,638 cubic inches.

4 0

4 years ago

WILL BRAINLIEST HURRY

inysia [295]

The correct answer would be the letter B

6 0

4 years ago

Read 2 more answers

SCALCET8 3.9.017.MI. Two cars start moving from the same point. One travels south at 48 mi/h and the other travels west at 20 mi

Veronika [31]

Answer:

The rate at which the distance between the cars increasing two hours later=52mi/h

Step-by-step explanation:

Let

Speed of one car, x'=48 mi/h

Speed of other car, y'=20 mi/h

We have to find the rate at which the distance between the cars increasing two hours later.

After 2 hours,

Distance traveled by one car

$x=48\times 2=96 mi$

Using the formula

$Distance=Time\times speed$

Distance traveled by other car

$y=20\times 2=40 mi$

Let z be the distance between two cars after 2 hours later

$z=\sqrt{x^2+y^2}$

Substitute the values

$z=\sqrt{(96)^2+(40)^2}$

z=104 mi

Now,

$z^2=x^2+y^2$

Differentiate w.r.t t

$2z\frac{dz}{dt}=2x\frac{dx}{dt}+2y\frac{dy}{dt}$

$z\frac{dz}{dt}=x\frac{dx}{dt}+y\frac{dy}{dt}$

Substitute the values

$104\frac{dz}{dt}=96\times 48+40\times 20$

$\frac{dz}{dt}=\frac{96\times 48+40\times 20}{104}$

$\frac{dz}{dt}=52mi/h$

Hence, the rate at which the distance between the cars increasing two hours later=52mi/h

3 0

3 years ago