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fredd [130]
3 years ago
7

The measures 4, 5, and 7 create a right triangle. True False

Mathematics
1 answer:
Korvikt [17]3 years ago
5 0

<em>False.</em>

Hope This Helps You!

Good Luck Studying ^-^

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For a continuous probablity distribution, 0 ≤ x ≤ 15. What is P(x &gt; 15)
sleet_krkn [62]

If the support of the distribution is 0 ≤ <em>x</em> ≤ 15, then <em>P</em>(<em>x</em> > 15) is always 0

3 0
3 years ago
My sister needs help with this please someone help her
olga2289 [7]

Answer:

1/5 ; 1.64

Step-by-step explanation:

Cara used 1.64 pints of blue paint or 1/5 of 8.2.

3 0
3 years ago
Read 2 more answers
What is the order from least to greatest: 2/6, 3/7, 5/12, and 4/10?
fenix001 [56]

Answer: Order from Least to Greatest

2/6 < 4/10 < 5/12 < 3/7

Step-by-step explanation:

6 0
3 years ago
Step by step explanation:<br><br> 12b - b =77
ozzi

Answer:

7

Step-by-step explanation:

12b -b = 11b

11b = 77

Divide both sides by 11

b = 7

8 0
3 years ago
Read 2 more answers
A bicyclist heads east at 10km/h. After she has traveled 24.2 kilometers, another cyclist sets out in the same direction going 3
Alona [7]
We know that the first cyclist has traveled 24.2 km at a speed of 10 km/h. Lets use the equation time= \frac{distance}{speed} to find the time of the first cyclist:
t= \frac{24.2}{10}
t=2.42
So, we know that she has traveled for 2.42 hours.
 
We also know that after she has traveled for 2.42 hours another<span> cyclist sets out in the same direction, so if </span>t represents the time of our first cyclist, <span>the time of our second cyclist will be </span>t-2.42.

Now we are going to use the equation distance=(speed)(time) to relate the speeds and times of the two cyclist:
For the first one:
distance=10t equation (1)
For the second one:
distance=30(t-2.42) equation (2)

Replace (1) in (2)
10t=30(t-2.42)
The only thing left now is solve for t:
10t=30t-72.6
-20t=-72.6
t= \frac{-72.6}{-20}
t=3.63

We can conclude that the second cyclist will catch up the first cyclist after 3.63 hours.


4 0
3 years ago
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