3 years ago

Solve the system by elimination -6x + 6y = 0 9x - 8y = 4

1 answer:

7 0

Answer:

Point form: (4, 4)

x = 4, y = 4

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Oksanka [162]

Answer:

$\boxed{\sf \ \ \ x^3-2x^2-19x+20 \ \ \ }$

Step-by-step explanation:

hello,

by definition we can write

$(x-5)(x+4)(x-1)$

as 5,-4,1 are the zeroes

now we have to write it in the standard form, let's do it

$(x-5)(x+4)(x-1)=(x^2+4x-5x-20)(x-1)\\=(x^2-x-20)(x-1)=x^3-x^2-20x-x^2+x+20\\=x^3-2x^2-19x+20$

hope this helps

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3 years ago

il63 [147K]

The answer is 66.6666%

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3 years ago

olga_2 [115]

The picture is super blurry so i can’t see anything

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3 years ago

erastova [34]

Answer:

x = 60°

Step-by-step explanation:

See picture below. When two parallel lines are cut by a transversal there are some special relationships.

4 0

2 years ago

fomenos

Use cosine rule:

c²=b²+a²-2ba cosC

Right triangle = 90 degrees
cosine 90 degrees = 0

c²=28²+15²-2×28×15×0
c²=28²+15²
c=√1009
c=31.8 in

5 0

3 years ago