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igomit [66]
3 years ago
9

Solve the system by elimination -6x + 6y = 0 9x - 8y = 4

Mathematics
1 answer:
jarptica [38.1K]3 years ago
7 0

Answer:

Point form: (4, 4)

x = 4, y = 4

You might be interested in
Identify the expression equivalent to 4x + x + 7) - 2x+8 - 4 by substituting x= 1 and x = 2. А. 6x + 11 B. 3(x+7) C. 2(3x + 16)
Alex

Answer:

4x + x + 7) - 2x+8 - 4 by substituting x= 1 and x = 2. А. 6x + 11 B. 3(x+7) C. 2(3x + 16) D. 3x + 16

Step-by-step explanation:

4 0
2 years ago
A theater has 50 seats on the front row. There are four additional seats in each following row. PART B: How many seats would the
Roman55 [17]
132, if you add four to 50, and keep going until you get to 20
7 0
3 years ago
At the start of the recovery period, the waterbuck population contained only 140 individuals. The population had 0.67 births per
Sergio [31]

Answer:

the intrinsic growth rate of the population = 0.67 - 0.06 = 0.61 or 61%

Step-by-step explanation:

since populations increase exponentially, the same will happen here

in 5 years the population should be:

P₅ = P₀e°⁶¹ˣ⁵ = 140e°⁶¹ˣ⁵ = 2,956.15 ≈ 2,956

in 10 years the population will be:

P₁₀ = P₀e°⁶¹ˣ¹⁰ = 140e°⁶¹ˣ¹⁰ = 62,420.09 ≈ 62,420

when you are using exponential growth rates, we have to assume that r will always remain constant

6 0
3 years ago
A drama club earns $1040 from a production. A total of 64 adult tickets and and 132 student tickets are sold. An adult ticket co
CaHeK987 [17]
A=adult ticket           s=student ticket                         

64a+132s=$1040
 a=2s
128a+132s=$1040
260tickets=$1040
$1040/260=$4
s=$4      (1s=$4x1)
a=$8      (2s=$4x2)

132s=$528       (132x$4)
64a=$512           (64x$8)
TOTAL=$1040 
5 0
3 years ago
Sketch the region enclosed by y=3x and y=x^2 . Then find the area of the region.
kolezko [41]

Answer:

A=4.5u^2

Step-by-step explanation:

The integral of a function gives you the area under the curve, the subtraction of one of the areas from the other will give you the area in between.

The limits of integration are the points where the curves intersect each other(take the curves has a system of equation and solve for x and y):

y=3x, y=x^2\\3x=x^2\\x^2-3x=0\\x(x-3)=0\\x_1=0\\x-3=0\\x_2=3

y_1=3x_1=3(0)=0\\y_2=3x_2=3(3)=9

The integral will be the subtraction of the curve y=3x and y=x^2  (In the graph you can see y=3x is the upper curve):

\int\limits^3_0 {3x-x^2} \, dx =\left\frac{3x^2}{2}-\frac{x^3}{3}\right|^3_0=\frac{3(3)^2}{2}-\frac{(3)^3}{3}-\left(\frac{3(0)^2}{2}-\frac{(0)^3}{3}\right)\\\int\limits^3_0 {3x-x^2} \, dx =\frac{27}{2}-\frac{27}{3} =13.5-9=4.5u^2

6 0
3 years ago
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