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Lana71 [14]
3 years ago
8

Helpppppppppppppppppppppp

Mathematics
1 answer:
castortr0y [4]3 years ago
7 0
Answer: second option y = 2(x + 7/2)^2 + 1/2

Explanation:

1) given:

y = (x + 3)^2 + (x + 4)^2

2) expand the binomials:

y = x^2 + 6x + 9 + x^2 + 8x + 16

3) add like terms:

y = 2x^2 + 14x + 25

4) take common factor 2 of the first two terms:

y = 2 (x^2 + 7x) + 25

5) complete squares for x^2 + 7x

x^2 + 7x = [x +(7/2)x ]^2 - 49/4

6) substitue x^2 + 7x = (x + 7/2)^2 - 49/4 in the equation for y:

y = 2 [ (x + 7/2)^2  - 49/4] + 25

7) take -49/4 out of the square brackets.

y = 2 (x + 7/2)^2 - 49/2 + 25

8) add like terms:

y = 2(x + 7/2)^2 + 1/2

And that is the vertex for of the given expression.

You might be interested in
Find the difference (7a-6b+7) - (8a-2)
olga nikolaevna [1]
Hey there!

Let's set up our expression:

(7a-6b+7)-(8a-2)

In order to simplify, we can use that subtraction sign and distribute it, using the distributive property. We have:

7a-6b+7-8a+2

Notice how it's plus two, because a negative times a negative two is a positive two. Now, it's a matter of finding the like terms and adding or subtracting them. These like terms can either have no variable, or have different coefficients but the same variable. That means our like terms are the 7a and -8a, and the 7 and 2. There's no like term for the 6b. That means we have:

(7a-8a) - 6b + (7+2) =

-a - 6b + 9

Hope this helps!
6 0
3 years ago
Find an equation for the line that passes through the points (5.-5) and (-4,-2)
ANEK [815]

Answer:

\large\boxed{y=-\dfrac{1}{3}x-\dfrac{10}{3}\to x+3y=-10}

Step-by-step explanation:

The slope-intercept form of an equation of a line:

y=mx+b

<em>m</em><em> - slope</em>

<em>b</em><em> - y-intercept</em>

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (5, -5) and (-4, -2).

Substiute:

m=\dfrac{-2-(-5)}{-4-5}=\dfrac{-2+5}{-9}=\dfrac{3}{-9}=-\dfrac{1}{3}

Put the value of the slope and the coordinates of the point (5, -5) to the equation of a line:

-5=-\dfrac{1}{3}(5)+b

-5=-\dfrac{5}{3}+b               <em>add 5/3 to both sides</em>

-\dfrac{15}{3}+\dfrac{5}{3}=b\\\\-\dfrac{10}{3}=b\to b=-\dfrac{10}{3}

Finally we have the equation of a line in the slope-intercept form:

y=-\dfrac{1}{3}x-\dfrac{10}{3}

Convert to the standard form <em>(Ax + By = C)</em>:

y=-\dfrac{1}{3}x-\dfrac{10}{3}          <em>multiply both sides by 3</em>

3y=-x-10              <em>add x to both sides</em>

x+3y=-10

4 0
3 years ago
Can someone help me please?
Marizza181 [45]

Answer:

about 6000π

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Given Sin x= 0.5, what is cos x?
Svetllana [295]
Sin x = 0.5
sin x = 1/2
sin x = opp/hyp
therefore the ratio of opp/hyp = 1/2, (opp = 1, hyp = 2)

Find the opp side

1² + x² = 2²
1 + x² = 4
x² = 4 -1
x² = 3
x =√3

The opp side is √3

cos x = opp/hyp = √3/2 = 0.87 (round to the nearest hundredths)
3 0
2 years ago
How to divide (x^2+5x-36)÷(x-4)
mr_godi [17]

Answer:

x + 9

Step-by-step explanation:

Since the divisor is in the form of <em>x - c</em>, use what is called <em>Synthetic Division</em>. Remember, in this formula, -c gives you the OPPOSITE terms of what they really are, so do not forget it. Anyway, here is how it is done:

4| 1 5 -36

↓ 4 36

----------------

1 9 0 → x + 9

You start by placing the c in the top left corner, then list all the coefficients of your dividend [x² + 5x - 36]. You bring down the original term closest to <em>c</em><em>,</em> then begin your multiplication. Now depending on what symbol your result is tells you whether the next step is to subtract or add, then you continue this process starting with multiplication all the way up until you reach the end. Now, when the last term is 0, that means you have NO REMAINDER. Finally, your quotient is one degree less than your dividend, so that 1 in your quotient can be an x, and the 9 follows right behind it, giving you the other factor of x + 9.

If you are ever in need of assistance, do not hesitate to let me know by subscribing to my channel [USERNAME: MATHEMATICS WIZARD], and as always, I am joyous to assist anyone at any time.

4 0
3 years ago
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