The mean length (rounded to 2 DP) of these 8 people's index finger is 5.83
<h3>What is the mean length (rounded to 2 DP) of these 8 people's index finger?</h3>
The given parameters are:
<u>Children</u>
Mean = 5.6 cm
Frequency = 5
<u>Adult</u>
Mean = 6.2 cm
Frequency = 3
The mean length of these 8 people's index finger is calculated as:

So, we have
Mean = (5.6 * 5 + 6.2 * 3)/(5 + 3)
Evaluate
Mean = 5.83
Hence, the mean length (rounded to 2 DP) of these 8 people's index finger is 5.83
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First list all the terms out.
e^ix = 1 + ix/1! + (ix)^2/2! + (ix)^3/3! ...
Then, we can expand them.
e^ix = 1 + ix/1! + i^2x^2/2! + i^3x^3/3!...
Then, we can use the rules of raising i to a power.
e^ix = 1 + ix - x^2/2! - ix^3/3!...
Then, we can sort all the real and imaginary terms.
e^ix = (1 - x^2/2!...) + i(x - x^3/3!...)
We can simplify this.
e^ix = cos x + i sin x
This is Euler's Formula.
What happens if we put in pi?
x = pi
e^i*pi = cos(pi) + i sin(pi)
cos(pi) = -1
i sin(pi) = 0
e^i*pi = -1 OR e^i*pi + 1 = 0
That is Euler's identity.
36 1/2 = 6
Given: the exponential expression
Answer:
38.29 i think
Step-by-step explanation:
Answer:
-46
Step-by-step explanation:
5 (x - 2) - 14x. x=4
5 (4 - 2) - 14(4) (distribute)
20 - 10 - 14(4) (multiply)
20 - 10 - 56 (subtract and solve.)
10 - 56 = -46 - solution
hope this helps (: