Answer:

Step-by-step explanation:


Hope it helps you!!
#IndianMurga(. ❛ ᴗ ❛.)
In the standard form of the equation
![\\ \ f(t)=Acos[b(t\pm c)]+k\\ \\](https://tex.z-dn.net/?f=%20%5C%5C%20%5C%20f%28t%29%3DAcos%5Bb%28t%5Cpm%20c%29%5D%2Bk%5C%5C%20%5C%5C%20)
The middle line =k
For our given problem
f(t) = 40cos (80t + 20)
On comparison we get k=0
Hence middle line=0
Answer:
The correct option is;
C. -3, multiplicity 2; -1, multiplicity 1; 1, multiplicity 1
Please find attached the required function graph
Step-by-step explanation:
To solve the equation f(x) = 2·x⁴ + 12·x³ + 16·x² -12·x - 18, by graphing the function, we have;
x
F(x)
-4
30
-3
0
-2
6
-1
0
0
-18
1
0
2
150
The shape of a graph with multiplicity of 2
Given that the graph bounces of the horizontal axis at the y-intercept at point x = -3, the factor (x - 3) must be a quadratic of the form (x - 3)², thereby having a multiplicity of 2 in the solution which are;
x = 1, -1, and, giving
(x - 1)·(x + 1)·(x - 3)² = 0
Therefore, the correct option is -3, multiplicity 2; -1, multiplicity 1; 1 multiplicity 1.
The mean is not needed to make a box plot.
I hoped this helped!
Answer:
N=0.019666a-0.983284 or
A = 50.85n + 50
Step-by-step explanation:
Let's solve for n.
a = 50 + 50.85n
Step 1: Flip the equation.
50.85n + 50 = a
Step 2: Add -50 to both sides.
50.85n+50+-50=a+-50
50.85n n = a - 50
Step 3: Divide both sides by 50.85.
50.85n
50.85
=
a-50
50.85
n=0.019666a-0.983284
Let's solve for a.
a = 50 + 50.85n