Answer: 67/9 or 7 4/9
Step-by-step explanation:
The square root of a a negative integer is imaginary.
It would still be a negative under a square root if you multiplied it by 2, therefor it will still be imaginary, or I’m assuming as your book calls it, undefined.
2•(sqrt-1) = 2sqrt-1
If you add a number to -1 itself, specifically 1 or greater it will become a positive number or 0 assuming you just add 1. In that case it would be defined.
-1 + 1 = 0
-1 + 2 = 1
If you add a number to the entire thing “sqrt-1” it will not be defined.
(sqrt-1) + 1 = 1+ (sqrt-1)
If you subtract a number it will still have a negative under a square root, meaning it would be undefined.
(sqrt-1) + 1 = 1 + (sqrt-1)
however if you subtract a negative number from -1 itself, you end up getting a positive number or zero. (Subtracting a negative number is adding because the negative signs cancel out).
-1 - -1 = 0
-1 - -2 = 1
If you squared it you would get -1, which is defined
sqrt-1 • sqrt-1 = -1
and if you cubed it, you would get a negative under a square root again, therefor it would be undefined.
sqrt-1 • sqrt-1 • sqrt-1 = -1 • sqrt-1 = -1(sqrt-1)
Sorry if this answer is confusing, I don’t have a scientific keyboard, I’ll get one soon.
Step-by-step explanation:
count the slope, 5 up in 2.5 horizontal steps, slope = 5/2.5 or 2
x intercept is on the graph, 2.5
y intercept is also on the graph, -5
Answer:
1. terms: 4r, 2, -6, and 3r like terms: 2 and -6, 4r and 3r
2.terms: 5h^2, -3h^2, - 4h, 3h, 7 like terms: 5h^2 and -3h^2, - 4h and 3h
3. 3m + 6
4. 15b + 2
5. 3x + 9
Step-by-step explanation:
1. 4r + 2 - 6 +3r
terms: 4r, 2, -6, and 3r like terms: 2 and -6, 4r and 3r
2. 5h^2 - 3h^2 - 4h + 3h + 7
terms: 5h^2, -3h^2, - 4h, 3h, 7 like terms: 5h^2 and -3h^2, - 4h and 3h
3. 6m + 7 - 3m-1
3m + 6
4. 3(5b +2) - 4
15b + 6 - 4
15b + 2
5. 2x + 4 + 5 + x
3x + 9
