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lianna [129]
3 years ago
8

SCALCET8 3.9.013. A plane flying horizontally at an altitude of 2 mi and a speed of 570 mi/h passes directly over a radar statio

n. Find the rate at which the distance from the plane to the station is increasing when it is 5 mi away from the station. (Round your answer to the nearest whole number.)
Mathematics
1 answer:
kkurt [141]3 years ago
7 0

Answer:

DL/dt = 529 miles/h

Step-by-step explanation:

The radio station (point A) the point just up the radio station ( point B), and the variable position of the plane ( at specif t  point C) shape a right triangle wich hypothenuse L is:

L²  =  d² + x²

d is the constant distance between the plane and the ground

Then differentiation with respect to time on both sides of the equation

2*L*dL/dt  = 2*d* Dd/dt  + 2*x*dx/dt

But   Dd/dt  =  0

L*dL/dt  =  x*dx/dt

x =  5 miles       dx/dt  =  570 m/h        L  = √ d² + x²    L  √ (5)² + (2)²

L = √29      L  = 5.39 m

5.39 *DL/dt  =  5*570 m/h

DL/dt  =   5*570/5.39   miles/h

DL/dt  =  528.76  miles/h

DL/dt = 529 miles/h

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The Earth rotates every 24 hr and as diameter of 7, 926 mi. If you're standing on the equator, how fast are you traveling in mil
Vlada [557]
<h3>Answer: Approximately 1038 mph</h3>

The more accurate value is 1037.51097384802

Round that however you need to.

=======================================

Explanation:

We need the circumference of the equator. Think of the equator as the largest possible circle (or belt) to fit around the earth.

C = pi*d

C = pi*7926

C = 7926pi

C = 24,900.2633723527

In 24 hours, a person at the equator travels roughly 24,900.2633723527 miles since the earth does a full rotation in this timespan.

Divide the two quantities distance over time to get the speed

rate = distance/time

rate = (24,900.2633723527 miles)/(24 hours)

rate = ( (24,900.2633723527)/(24) ) miles per hour

rate = 1,037.51097384802

rate = 1038 mph

I'm rounding to 4 sig figs since the diameter is given to be in four sig figs.

This speed of roughly 1038 mph is a linear speed and not an angular speed.

-----------------------------

Extra info (optional section)

Upon further research, I found an article from NASA JPL (jet propulsion laboratory) which states quote:

<em>"To make one complete rotation in 24 hours, a point near the equator of the Earth must move at close to 1000 miles per hour (1600 km/hr)"</em>

Their figure of 1000 mph seems to be a rough estimate, more or less. It's fairly close to the 1038 figure we got earlier.

8 0
3 years ago
How would you write 0.7 as a fraction?
Paul [167]
0.7 as a fraction would be 7/10
3 0
3 years ago
(x^3+4x^2-4x+46)/(x^2-5x+6)
valentinak56 [21]

Step-by-step explanation:  x 2 − 5 x + 6  using the AC method. x 3 + 4 x 2 − 4 x + 46 ( x −3 ) ( x − 2 )

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Which is equivalent to the following expression? (2x^2+4xy-y^2)+(x^2+3xy-y^2)
masya89 [10]

annswer:

−

80


Explanation:

2

(

2

)

2

+

[

3

(

2

)

(

−

4

)

]

−

4

(

−

4

)

2


2

(

4

)

+

[

−

24

]

−

4

(

16

)


8

−

24

−

64

=

8

−

88

=

−

80


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