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pentagon [3]
3 years ago
7

Omg plsss someone help i rly don't get this question!!! TYY

Mathematics
2 answers:
Bogdan [553]3 years ago
5 0
Answer: 65856in I think you only have to multiply both of the numbers and this is what I got
finlep [7]3 years ago
4 0
Ok sorry but I see someone is online can you help
With a science question
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Solve the equation using the method of completing the square. 2x^2 + 16 - 8 = 0
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is 12 ggggzhhdhsjshsbMjd zmesnmnr fs kn fs jxj
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A lighthouse keeper has a 10 degrees angle of depression between the horizontal light beam and the line of sight from the ship.
Andrei [34K]
107.75m
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4 0
3 years ago
Assume a simple random sample of 10 BMIs with a standard deviation of 1.186 is selected from a normally distributed population o
kirza4 [7]

Answer:

a) H0: \sigma = 1.34

H1: \sigma \neq 1.34

b) df = n-1= 10-1=9

And the critical values with \alpha/2=0.005 on each tail are:

\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589

c) t=(10-1) [\frac{1.186}{1.34}]^2 =7.05

d) For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

Step-by-step explanation:

Information provided

n = 10 sample size

s= 1.186 the sample deviation

\sigma_o =1.34 the value that we want to test

p_v represent the p value for the test

t represent the statistic  (chi square test)

\alpha=0.01 significance level

Part a

On this case we want to test if the true deviation is 1,34 or no, so the system of hypothesis are:

H0: \sigma = 1.34

H1: \sigma \neq 1.34

The statistic is given by:

t=(n-1) [\frac{s}{\sigma_o}]^2

Part b

The degrees of freedom are given by:

df = n-1= 10-1=9

And the critical values with \alpha/2=0.005 on each tail are:

\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589

Part c

Replacing the info we got:

t=(10-1) [\frac{1.186}{1.34}]^2 =7.05

Part d

For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

5 0
2 years ago
Lucy Baker is analyzing demographic characteristics of two television programs: COPS (population 1) and 60 Minutes (population 2
drek231 [11]

Answer and Explanation:

Her alternative hypothesis is that there is some difference between the means of the ages of the audiences of the two television programs. That is, the mean ages of the two audiences are not the same.

If the mean of the ages of the audiences of television programme 1 (COPS) is xbar₁

And the mean of the ages of the audiences of the television programme 2 (60 minutes) is xbar₂

Her alternative hypothesis can be represented mathematically as

xbar₁ - xbar₂ ≠ 0

7 0
2 years ago
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