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zlopas [31]
3 years ago
11

Https://brainly.com/question/20878483

Mathematics
1 answer:
snow_tiger [21]3 years ago
3 0

Answer:

Oh okayy

Step-by-step explanation:

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How many 1-centimeter squares fit along the length of the rectangle
Damm [24]
It would depend on how large the rectangle is
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3 years ago
How do you find your y-intercept from your x-y points?
PSYCHO15rus [73]
1. To determine the x-intercept, we set y equal to zero and solve for x. Similarly, to determine the y-intercept, we set x equal to zero and solve for y. ...

2. To find the x-intercept, set y = 0 \displaystyle y=0 y=0.

3. To find the y-intercept, set x = 0 \displaystyle x=0 x=0.
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2 years ago
Complete the input-output table for the linear function y = 3x.<br><br> a= b= c=
Helen [10]

Answer:

The answer would be A. 1 1/5

48/40 = 1 8/40

1 8/40 Simplify to 1 1/5

Hope this helps!

Step-by-step explanation:

4 0
4 years ago
Solve for x: 5x + 4z = 10z - 2x
Digiron [165]

Answer:

x= 6/7z

Step-by-step explanation:

5x + 4z = 10z - 2x

5x + 2x = 10z - 4z

7x = 6z

x = 6/7z

5 0
3 years ago
Read 2 more answers
A rectangle is inscribed with its base on the x-axis and its upper corners on the parabola y=2−x2. What are the dimensions of su
Paul [167]

Answer:

Step-by-step explanation:

Given that a rectangle is inscribed with its base on the x-axis and its upper corners on the parabola

y=2-x^2

the parabola is open down with vertex at (0,2)

We can find that the rectangle also will be symmetrical about y axis.

Let the vertices on x axis by (p,0) and (-p,0)

Then other two vertices would be (p,2-p^2) (-p,2-p^2) because the vertices lie on the parabola and satisfy the parabola equation

Now width = 2-p^2

Area = l*w = 2(2p-p^3)

Use derivative test

I derivative = 2(2-3p^2)

II derivative = -12p

Equate I derivative to 0 and consider positive value only since we want maximum

p = \sqrt{\frac{2}{3} }

Thus width= \sqrt{\frac{2}{3} }

Length =2\sqrt{\frac{2}{3} }

Width = 2-2/3 = 4/3

3 0
3 years ago
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