Help please . thank you

Which number line correctly shows 1. 5 + 2. 5? A number line going from 0 to 6. 5 in increments of 0. 5. An arrow goes from 0 to

Usimov [2.4K]

So we want to see which number line shows the sum 1.5 + 2.5. We will see that the correct option is "An arrow goes from 0 to 1. 5 and from 1. 5 to 4"

So the number line usually starts at 0 and goes to the first number, 1.5 in this case.

Then, it moves accordingly to the second number, 2.5 (so it will move 2.5 units to the right)

So the number line should start at 0 and move to the right until it meets 1.5 + 2.5 = 4.

From the options, the only that is correct is:

"An arrow goes from 0 to 1. 5 and from 1. 5 to 4"

If you want to learn more about number lines, you can read:

brainly.com/question/10851163

6 0

2 years ago

Simplify.

sergey [27]

2y+7z hope this helped dude

6 0

3 years ago

Read 2 more answers

Use the number chart to answer the questions. Circle each number you find. You can only use digits that are next to each other t

NARA [144]

Answer:

row - F
column - K
column - S
row - B
column - K
column - G

Step-by-step explanation:

1. The least four digit number found in the rows is : 1164

The row is F

2. The maximum number of digits in counting order is : 1 3 5 7 9

The column is K

3. The highest 3 digit number in a column is 992

The column is S

4. The palindrome with greatest number of digits is 7117

The row is B

5. The greatest number of odd numbers in counting order is : 1 3 5 7 9

The column is K

6. The palindrome with greatest number of digits is 235532

The column is G

7 0

3 years ago

Find the derivative of the function f(x) = (x3 - 2x + 1)(x – 3) using the product rule.

julsineya [31]

Answer:

Step-by-step explanation:

Hello, first, let's use the product rule.

Derivative of uv is u'v + u v', so it gives:

$f(x)=(x^3-2x+1)(x-3)=u(x) \cdot v(x)\\\\f'(x)=u'(x)v(x)+u(x)v'(x)\\\\ \text{ **** } u(x)=x^3-2x+1 \ \ \ so \ \ \ u'(x)=3x^2-2\\\\\text{ **** } v(x)=x-3 \ \ \ so \ \ \ v'(x)=1\\\\f'(x)=(3x^2-2)(x-3)+(x^3-2x+1)(1)\\\\f'(x)=3x^3-9x^2-2x+6 + x^3-2x+1\\\\\boxed{f'(x)=4x^3-9x^2-4x+7}$

Now, we distribute the expression of f(x) and find the derivative afterwards.

$f(x)=(x^3-2x+1)(x-3)\\\\=x^4-2x^2+x-3x^3+6x-4\\\\=x^4-3x^3-2x^2+7x-4 \ \ \ so\\ \\\boxed{f'(x)=4x^3-9x^2-4x+7}$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

6 0

3 years ago

Line A: y=-1/2x+3

sashaice [31]

A) For the equation $y=- \frac{1}{2}x+3$ , the slope is $- \frac{1}{2}$ .
Slope-intercept form is y = mx + b, where m is slope and b is the y-intercept. This means that if $m=- \frac{1}{2}$ , the slope is $- \frac{1}{2}$ .

B) Since this equation is in the same form, you just find what m is equal to.
Since $m=2$ , that's the slope.

For the solution, set $y=- \frac{1}{2}x+3$ equal to $y=2x-4$ , so it would be put together like this:
$y=[tex]- \frac{1}{2}x+3=2x-4\\ -\frac{1}{2}=2x-7\\ 1\frac{1}{2}x=-7\\ x=-4.66667$
So your answer is -4.667.

8 0

3 years ago