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Nonamiya [84]
3 years ago
13

Halpppppppppppp i don't understand this... <:

Mathematics
1 answer:
ollegr [7]3 years ago
8 0

Answer:

B

Step-by-step explanation:

It already says the cost depends on the area of the walls.

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Which number is a perfect cube? a.21 b.49 c.343 d.600
melisa1 [442]
C. 343 because <span>A perfect cube is the result of multiplying a number </span>three<span> times by itself. 

1, 8, 27, 64, 125, 216, 343, and so on


</span>
5 0
3 years ago
Read 2 more answers
Which of the following sets are subspaces of R3 ?
Ratling [72]

Answer:

The following are the solution to the given points:

Step-by-step explanation:

for point A:

\to A={(x,y,z)|3x+8y-5z=2} \\\\\to  for(x_1, y_1, z_1),(x_2, y_2, z_2) \varepsilon A\\\\ a(x_1, y_1, z_1)+b(x_2, y_2, z_2) = (ax_1+bx_2,ay_1+by_2,az_1+bz_2)

                                        =3(aX_l +bX_2) + 8(ay_1 + by_2) — 5(az_1+bz_2)\\\\=a(3X_l+8y_1- 5z_1)+b (3X_2+8y_2—5z_2)\\\\=2(a+b)

The set A is not part of the subspace R^3

for point B:

\to B={(x,y,z)|-4x-9y+7z=0}\\\\\to for(x_1,y_1,z_1),(x_2, y_2, z_2) \varepsilon  B \\\\\to a(x_1, y_1, z_1)+b(x_2, y_2, z_2) = (ax_1+bx_2,ay_1+by_2,az_1+bz_2)

                                             =-4(aX_l +bX_2) -9(ay_1 + by_2) +7(az_1+bz_2)\\\\=a(-4X_l-9y_1+7z_1)+b (-4X_2-9y_2+7z_2)\\\\=0

\to a(x_1,y_1,z_1)+b(x_2, y_2, z_2) \varepsilon  B

The set B is part of the subspace R^3

for point C: \to C={(x,y,z)|x

In this, the scalar multiplication can't behold

\to for (-2,-1,2) \varepsilon  C

\to -1(-2,-1,2)= (2,1,-1) ∉ C

this inequality is not hold

The set C is not a part of the subspace R^3

for point D:

\to D={(-4,y,z)|\ y,\ z \ arbitrary \ numbers)

The scalar multiplication s is not to hold

\to for (-4, 1,2)\varepsilon  D\\\\\to  -1(-4,1,2) = (4,-1,-2) ∉ D

this is an inequality, which is not hold

The set D is not part of the subspace R^3

For point E:

\to E= {(x,0,0)}|x \ is \ arbitrary) \\\\\to for (x_1,0 ,0) ,(x_{2},0 ,0) \varepsilon E \\\\\to  a(x_1,0,0) +b(x_{2},0,0)= (ax_1+bx_2,0,0)\\

The  x_1, x_2 is the arbitrary, in which ax_1+bx_2is arbitrary  

\to a(x_1,0,0)+b(x_2,0,0) \varepsilon  E

The set E is the part of the subspace R^3

For point F:

\to F= {(-2x,-3x,-8x)}|x \ is \ arbitrary) \\\\\to for (-2x_1,-3x_1,-8x_1),(-2x_2,-3x_2,-8x_2)\varepsilon  F \\\\\to  a(-2x_1,-3x_1,-8x_1) +b(-2x_1,-3x_1,-8x_1)= (-2(ax_1+bx_2),-3(ax_1+bx_2),-8(ax_1+bx_2))

The x_1, x_2 arbitrary so, they have ax_1+bx_2 as the arbitrary \to a(-2x_1,-3x_1,-8x_1)+b(-2x_2,-3x_2,-8x_2) \varepsilon F

The set F is the subspace of R^3

5 0
3 years ago
Negative 15 plus 45 divided by 3
Furkat [3]

Answer:

10

Step-by-step explanation:

(-15+45)/3=10

3 0
3 years ago
8th grade math Ik but I do need help though
kramer

Answer:

x =-4

Step-by-step explanation:

4x+9 = -2x-15

Add 2x to each side

4x+2x +9 = -2x+2x-15

6x+9 = -15

Subtract 9 from each side

6x +9-9=-15-9

6x = -24

Divide each side by 6

6x/6 = -24/6

x = -4

7 0
3 years ago
Christina buys 3 DVDs . 2 of the DVDs cost X+Y . Write an expression that shows the amount the 3 DVDs cost
-BARSIC- [3]

Answer:

3/2(x+y)

Step-by-step explanation:

The cost of 2 DVD is x+y

Divide by 2 to get the cost of one DVD

(x+y) /2

Multiply by 3 to get the cost of 3

3/2(x+y)

7 0
2 years ago
Read 2 more answers
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