1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
nexus9112 [7]
2 years ago
13

I ate 4/9 of a ceral box how much ceral do i have left in the box

Mathematics
2 answers:
Solnce55 [7]2 years ago
7 0

Answer:

5/9 of the cereal box.

Hope this helped! :)

Naddik [55]2 years ago
4 0
You have 5/9 of cereal left in the box
You might be interested in
A system of equations is given below:
My name is Ann [436]
Solving by substitution:

y = 4x - 3 

2x + 7y = 41

Let us substitute the first equation y = 4x - 3  into the second.

2x + 7y = 41

2x + 7(y = 4x -3) = 41

2x + 7(4x -3) = 41

So that's the third option.

I hope this helps.
4 0
3 years ago
Read 2 more answers
A Japanese bullet train travels 558 miles per 3 hours A. What is the rate B. How far does the train travel in 1 hour WHO EVER A
Delicious77 [7]

Answer:

Step-by-step explanation:

Remark

The rate is going to be the same as the distance travelled in 1 hour. The units will be different.

Formula

d = r * t

Givens

d = 558 miles

t = 3 hours

Problem A

r = d / t

r = 558/ 3 = 186 miles / hr

Problem B

Givens

r = 186 miles / hour

t = 1 hour

d = ?

Solution

d = 186 mi/hr * 1 hr

d = 186 miles

<u>Note</u>

This looks really trivial, but it's not. You have to learn to see the difference between a number and its units. It's not very often that the numbers will be the same, but if the units differ, then it is an entirely different question.

7 0
2 years ago
HELP 1 QUESTION!! IREADY!!! EXPLAIN!!
Anit [1.1K]
The linear equation (y = mx + b) for this particular line is d = 0.6t
it's the same as finding the equation for any line except they use d instead of y and t instead of x. The slope m is 0.6 and intercept is zero.
4 0
2 years ago
A fair die is cast four times. Calculate
svetlana [45]

Step-by-step explanation:

<h2><em><u>You can solve this using the binomial probability formula.</u></em></h2><h2><em><u>You can solve this using the binomial probability formula.The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.</u></em></h2><h2><em><u>You can solve this using the binomial probability formula.The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.Then, we can set the equation as follows:</u></em></h2><h2><em><u>You can solve this using the binomial probability formula.The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.Then, we can set the equation as follows: </u></em></h2><h2><em><u>You can solve this using the binomial probability formula.The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.Then, we can set the equation as follows: P(X≥x) = ∑(k=x to n) C(n k) p^k q^(n-k) </u></em></h2><h2><em><u>You can solve this using the binomial probability formula.The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.Then, we can set the equation as follows: P(X≥x) = ∑(k=x to n) C(n k) p^k q^(n-k) n=4, x=2, k=2</u></em></h2><h2><em><u>You can solve this using the binomial probability formula.The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.Then, we can set the equation as follows: P(X≥x) = ∑(k=x to n) C(n k) p^k q^(n-k) n=4, x=2, k=2when x=2 (4 2)(1/6)^2(5/6)^4-2 = 0.1157</u></em></h2><h2><em><u>You can solve this using the binomial probability formula.The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.Then, we can set the equation as follows: P(X≥x) = ∑(k=x to n) C(n k) p^k q^(n-k) n=4, x=2, k=2when x=2 (4 2)(1/6)^2(5/6)^4-2 = 0.1157when x=3 (4 3)(1/6)^3(5/6)^4-3 = 0.0154</u></em></h2><h2><em><u>You can solve this using the binomial probability formula.The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.Then, we can set the equation as follows: P(X≥x) = ∑(k=x to n) C(n k) p^k q^(n-k) n=4, x=2, k=2when x=2 (4 2)(1/6)^2(5/6)^4-2 = 0.1157when x=3 (4 3)(1/6)^3(5/6)^4-3 = 0.0154when x=4 (4 4)(1/6)^4(5/6)^4-4 = 0.0008</u></em></h2><h2><em><u>You can solve this using the binomial probability formula.The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.Then, we can set the equation as follows: P(X≥x) = ∑(k=x to n) C(n k) p^k q^(n-k) n=4, x=2, k=2when x=2 (4 2)(1/6)^2(5/6)^4-2 = 0.1157when x=3 (4 3)(1/6)^3(5/6)^4-3 = 0.0154when x=4 (4 4)(1/6)^4(5/6)^4-4 = 0.0008Add them up, and you should get 0.1319 or 13.2% (rounded to the nearest tenth)</u></em></h2>
8 0
3 years ago
-14n + q=rt-4n, for n
pentagon [3]
N = -1/10rt + 1/10q
= −14n+q+4n=rt−4n+4n
= −10n+q=rt
= −10n+q+−q=rt+−q
= −10n=rt−q
= -10n/-10 = rt-q/-10
So the answer is:
= n = -1/10rt + 1/10q
3 0
3 years ago
Read 2 more answers
Other questions:
  • Mr. Roberts collected data to determine how many birds were at his bird feeder during different times of the day. Identify the s
    10·2 answers
  • How do I convert 2/5 to a decimal
    6·2 answers
  • PLEASE HELP!!
    8·2 answers
  • The question: how old am I if 400 reduced by 2 times my age is 352?
    8·1 answer
  • a jar only 11 red balls, 9 yellow balls, 5 green balls, and n white balls. what is the probability that a ball randomly chosen f
    11·1 answer
  • A consistent, dependent system of equations is a system with __________. (1 point)
    8·1 answer
  • Can someone help me here thx!
    14·2 answers
  • Helppppp<br> me anyone :(
    12·2 answers
  • I’m giving brainliest !!!
    8·1 answer
  • Urgent
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!