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faust18 [17]
3 years ago
11

Please help me if you can, thank you so much

Mathematics
1 answer:
galben [10]3 years ago
8 0
D)

The slope (number with x variable) is negative because the line points down.

The y intercept is currently at 1.. if shifted up 2 units it would be at 3
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At the end of January of last year, stock A was selling at A dollars a share, and stock B was selling a B dollars a share, where
Maslowich

Answer: a) yNA/100

b) NA(y-x)/100

c) (NA)/B

Step-by-step explanation:

a) The total amount of dollars owned by the shares' owner = N number of shares × A dollars per share = NA dollars

This total is then transferred to buy B shares which then appreciates by y%.

The amount of increase in portfolio from January to June = y% of total dollars invested = y% of NA dollars = yNA/100

b) If the shares were left with A, the increase in portfolio from January to June would be x% and = x% of the total Dollar amount = x% of NA dollars = xNA/100

How much more money made in that time would be the difference in interest, between taking the dollars to invest in share B or keeping the dollars on investment A

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3 0
3 years ago
Write an equation that represents the line?
yarga [219]

Answer:

An equation that represents the line is:

y = 3/4x - 9/2

Step-by-step explanation:

The slope-intercept form of the line equation

y = mx+b

where

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  • b is the y-intercept

Given the attached graph of a line.

Taking two points from the line, such as

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Determining the slope between (2, -3) and (0, 6)

\left(x_1,\:y_1\right)=\left(2,\:-3\right),\:\left(x_2,\:y_2\right)=\left(6,\:0\right)

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refine

m=\frac{3}{4}

substituting m = 3/4 and the point (2, -3) in the slope-intercept form of the line equation

y = mx + b

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subtract 3/2 from both sides

\frac{3}{2}+b-\frac{3}{2}=-3-\frac{3}{2}

b=-\frac{9}{2}

now substituting b = -9/2 and m = 3/4 in the slope-intercept form of the line equation

y = mx + b

y = 3/4x + (-9/2)

Therefore, an equation that represents the line is:

y = 3/4x - 9/2

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3 years ago
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Answer:

he has received negative positive punishment...? I"M SORRY IF IT"S WRONG!!!

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The answer to this question is:

<span>If a quadratic equation can be factored and each factor contains only real numbers then there cannot be an imaginary solution?
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