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2 years ago

Calculate the volume of the figure below.

Mathematics

1 answer:

Grace [21]2 years ago

4 0

Answer:

4080 cm³

Step-by-step explanation:

Figure is of a cuboid

Given length (l) = 30cm

breadth (b) = 17cm

height (h) = 8cm

Volume of cuboid = l.b.h

= 30 × 17 × 8

= 4080 cm³

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aleksandrvk [35]

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Step-by-step explanation:

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3 years ago

Avaluate 2^3x-1 for x=1

DENIUS [597]

Answer:

4 or 7 (Check the explanation to see which one your equation actually is.

Step-by-step explanation:

One thing I want to clarify for you, It's Evaluate, not Avaluate.

Okay so, we want to find the value of 2^3x-1 and we know x = 1.

You didn't really clarify if the expression was $2^{3x-1}$ or $2^{3x}-1$ , so I'll be doing both:

For $2^{3x-1}$ , we should plug in x to get $2^{3(1)-1}$ and then simplify to get $2^{2}$ .

2 to the power of 2 or $2^{2}$ is equal to 2 * 2 or 4.

The second one, $2^{3x}-1$ , we should plug in x to get $2^{3(1)}-1$ and then to become $2^{3}-1$ . 2 to the power of 3 or $2^{3}$ is 8 and then minus 1 is 7.

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3 years ago

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Point A’ is the image of Point A when point A is rotated about the origin B. What angle in the counterclockwise direction is A r

liberstina [14]

Answer:

90 degrees

Step-by-step explanation:

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2 years ago

The temperature of a weather station was 12.8 °F at midnight and fell 1.4 °F each hour for six hours. Which of the following sol

Len [333]

Answer:

Let's try to find a linear relation like:

T(h) = a*h + b

where a is the slope and b is the y-intercept.

h is the number of hours after midnight.

T is the temperature at the time defined by h.

We know that at midnight, the temperature is 12.8°F.

At midnight, we have h = 0, then:

T(0) = a*0 + b = 12.8°F

b = 12.8°F

Now we know that our function is:

T(h) = a*h + 12.8°F

We also know that the temperature fell 1.4 °F each hour for six hours.

Then the slope will be -1.4°F

We can write the linear relationship as:

T(h) = -1.4°F*h + 12.8°F (for 0 ≤ h ≤ 6)

Where we have a restriction in the possible values of h, because we know that this model only works for six hours after midnight,

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2 years ago

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IL COSL al we creeree viall

kakasveta [241]

Answer:

In the next year, Anthony worked 2,084 hours

Step-by-step explanation:

Anthony worked 1,697 hours in 2010.

We also know Anthony worked 22.8% more hours than in 2010.

The problem requires to calculate how much did Anthony work in the next year.

It can be calculated as follows:

Take 22.8% of 1,697:

$22.8 * 1,697 / 100 = 386.916\approx 387\ hours$

Now calculate by adding it to the original number of hours:

1,697 + 387 = 2,084 hours

In the next year, Anthony worked 2,084 hours

8 0

3 years ago