Step-by-step explanation:
-3,4 Is the answer Is it right or wrong if it is true plz mark me as brainliest
Answer:
<MKL=27
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The question is missing some parts. To complete, J is the event of getting a jack and R is getting a red card.
The first question is to look for the P (J) and P (R) =
P (J) = 4/52 = 0.077; since there are only 4 jacks in a standard deck.
P (R) = 26/52 = 0.5; 26 because there are 13 each for diamonds and hearts.
The second question is to describe the event J and R in words. Then look for that event’s probability.
The card is a red jack or the card is red and a jack. P (J and R) = 2/52 = 0/038
The last question is explain why P (J or R) is not equal to P (J) + P (R). Then use the general addition rule to compute for P (J or R).
The event card is red and card is jack are not mutually exclusive meaning two or more events can happen simultaneously. Thus one will count two cards twice unless using the general probability addition formula.
The probability for P (J ∪ R) is:P (J ∪ R) = 2 + 2 + 24 / 52 = 28/52 = 0.0538Or the other solution would be:P (J ∪ R) = 4/52 + 26/52 + 2/52 = 28/52 = 0.0538
Answer:
Step-by-step explanation:
For this case we want to find the density function for 
And we have the following density function for the random variable X:
So we can do this replacing 
If we apply square root on both sides we got:
And if we integrate we got this:
![F_Y (y) = [t+ \frac{t^2}{2}] \Big|_{-\sqrt{y}}^0+ [t -\frac{t^2}{2}] \Big|_{0}^{\sqrt{y}}](https://tex.z-dn.net/?f=%20F_Y%20%28y%29%20%3D%20%5Bt%2B%20%5Cfrac%7Bt%5E2%7D%7B2%7D%5D%20%5CBig%7C_%7B-%5Csqrt%7By%7D%7D%5E0%2B%20%5Bt%20-%5Cfrac%7Bt%5E2%7D%7B2%7D%5D%20%5CBig%7C_%7B0%7D%5E%7B%5Csqrt%7By%7D%7D%20)
And replacing we got:
![F_Y (y) = [0 -(-\sqrt{y} +\frac{y}{2})] + [\sqrt{y} -\frac{y}{2}]](https://tex.z-dn.net/?f=%20F_Y%20%28y%29%20%3D%20%5B0%20-%28-%5Csqrt%7By%7D%20%2B%5Cfrac%7By%7D%7B2%7D%29%5D%20%2B%20%5B%5Csqrt%7By%7D%20-%5Cfrac%7By%7D%7B2%7D%5D)
And if we want to find the density function we just need to derivate the pdf like this:
