Answer:
<u></u>
Explanation:
The complete question is:
<em>Between the time iko woke up and lunchtime, the temperature rose by 11º. Then by the time he went to bed, the temperature dropped by 14º.</em>
<em />
<em>Write an addition expression for the temperature relative to when iko woke up. </em>
<em />
<h2>Solution</h2>
It is said that between the time Iko woke up and lunchtime, the temperature rose by 11 degrees. A rise means the temperature increased and you must add 11º.
Then, relative to when Iko woke up the temperature is:
Then, by the time Iko went to bed, the temperature dropped by 14º. A drop means that the change is negative. This means that you must add a negative number, and the additive expression is:
If you want the overall change in temperature you do the operation:
- 11 + (-14) = 11 - 14 = - 3. A net decrease of 3º.
But the answer to this question is the additive expression:
B. 12 would be your answer
4(-3x)=y F f f f f f f f d d d d d d d d d d d d d d d d d d d d d d
4 answers · Mathematics
Best Answer
We will need to split the middle term and use the grouping method. To do this multiply the coefficient of the first term (6) against the coefficient of the last term (10):
6 * 10 = 60
Factors of 60 = +-(1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60)
From the list of factors find two numbers that when added together give -19 and when multiplied together give 60. -15 and -4 added together give -19 and multiplied together give 60 so split the middle term by rewriting these values back into the expression:
6x^2 - 15xy - 4xy + 10y^2
Now use the grouping method, take out the highest common factor between the two sets of terms:
3x(2x - 5y) - 2y(2x - 5y)
Group the outside terms:
(3x - 2y)(2x - 5y)
Answers
6 = -3*-2
10 = 5*2
5*3+2*2=19
thus
(2y-3x)(5y-2x)
