Ok, so it seems to be the square root of the cube root of 2
we just convert to exponential
remember
and
![\sqrt[n]{x^m} =x^ \frac{m}{n}](https://tex.z-dn.net/?f=%20%5Csqrt%5Bn%5D%7Bx%5Em%7D%20%3Dx%5E%20%5Cfrac%7Bm%7D%7Bn%7D%20)
therfor
![\sqrt{ \sqrt[3]{2} }= \sqrt{2^ \frac{1}{3} } =( 2^ \frac{1}{3})^ \frac{1}{2} =2^ \frac{1}{6}](https://tex.z-dn.net/?f=%20%5Csqrt%7B%20%5Csqrt%5B3%5D%7B2%7D%20%7D%3D%20%5Csqrt%7B2%5E%20%5Cfrac%7B1%7D%7B3%7D%20%7D%20%3D%28%202%5E%20%5Cfrac%7B1%7D%7B3%7D%29%5E%20%5Cfrac%7B1%7D%7B2%7D%20%3D2%5E%20%5Cfrac%7B1%7D%7B6%7D%20%20)
last choice is correct
we just convert to exponential
remember
therfor
last choice is correct
Which list orders from least to greatest?
1 answer:
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