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3 years ago

P & Q are midpoint of side CA & CB respectively of ΔABC right angled at C. Prove that 4( AQ² + BP² ) = 5AB²

Mathematics

1 answer:

AleksAgata [21]3 years ago

3 0

Yes the right ANSER is AQ/4 because if you did 2 + 2 is four and the 4 divide by 4 it equals to 4

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What is the slope of line PQ?

Scilla [17]

we know that

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

Part a) Find the slope of line PQ

$P(-8,2)\ Q(4,2)$

substitute in the formula

$m=\frac{2-2}{4+8}$

$m=\frac{0}{12}=0$

Any line parallel to X-axis has slope equal to zero

the line PQ is parallel to the x-axis

therefore

the answer Part a) is

$0$

Part b) Find the slope of line MN

$M(8,6)\ N(8,-8)$

substitute in the formula

$m=\frac{-8-6}{8-8}$

$m=\frac{-14}{0}$

Anything divided by zero is undefined

m=undefined

therefore

the answer Part b) is

undefined

Part c) How are the two lines related ?

we know that

Any line perpendicular to X-axis has slope undefined

Because the term $(x2-x1)$ will always be zero

the answer Part c) is

the lines are perpendicular

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