Answer:
YZ = 44
Step-by-step explanation:
Let the intersection of XW and YZ equal A. For this problem, we can use power of a point in the scenario where two secants intersect in the interior of a circle. We get the equation:
WA * AX = ZA * AY
We can substitute the values we are given to get:
(2x - 6)(21) = (x + 1)(30)
42x - 126 = 30x + 30
12x - 126 = 30
12x = 156
x = 13
Using segment addition postulate, we can say that:
YZ = YA + AZ
And we can plug in what we know from the diagram:
YZ = 30 + x + 1
We can also plug in the value of x, 13
YZ = 30 + 13 + 1 = 44
Well it looks really simple I'm gonna go with 5
A line graph <span>is useful for showing changes over a period of time.
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The graph of any quadratic equation y=ax2+bx+c y = a x 2 + b x + c , where a, b, and c are real numbers and a≠0 a ≠ 0 , is called a parabola. When graphing parabolas, find the vertex and y-intercept. ... This y-value is a maximum if the parabola opens downward, and it is a minimum if the parabola opens upward.
Vertex: (−1, 3)
Y-intercept: (0, 5)
X-intercepts: None
Extra points: (−3, 11), (−2, 5), (1, 11)
