Simplify the log expression

What is the third quartile of this data set ? 14,18,20,21,25,32,40,44,48

kotykmax [81]

42

Step-by-step explanation:

Step 1 :

Given data set - 14,18,20,21,25,32,40,44,48

We need to get the 3rd quartile

Step 2 :

To find the quartile's , we have to divide the data set into 4 equal quarters.

The 3rd cut will give the 3rd quartile

Step 3:

The median of this data set is at 25, there are 4 numbers below and above it.

Now we take the 2nd half of the set , after the median and take the median of it.

There are 4 numbers in the 2nd half 32,40,44,48. Cutting this into 2 , we have the cut to fall between 40 and 44. Hence taking the average of this will give the 3rd quartile.

The average of 40 and 44 is 42 .

Hence the 3rd quartile is 42.

7 0

3 years ago

(Brainliest for fastest right answer!!) Which is correct?

Arisa [49]

Answer:

Step-by-step explanation:

a² - b² = (a - b)(a + b)

n² - 25 = n² - 5² = <em>(n - 5)(n + 5)</em>

7 0

2 years ago

why do we need imaginary numbers?explain how can we expand (a+ib)^5. finally provide the expanded solution of (a+ib)^5.(write a

zheka24 [161]

Answer:

a. We need imaginary numbers to be able to solve equations which have the square-root of a negative number as part of the solution.

b. (a + ib)⁵ = a⁵ + 5ia⁴b - 10a³b² - 10ia²b³ + 5ab⁴ + ib⁵

Step-by-step explanation:

a. Why do we need imaginary numbers?

We need imaginary numbers to be able to solve equations which have the square-root of a negative number as part of the solution. For example, the equation of the form x² + 2x + 1 = 0 has the solution (x - 1)(x + 1) = 0 , x = 1 twice. The equation x² + 1 = 0 has the solution x² = -1 ⇒ x = √-1. Since we cannot find the square-root of a negative number, the identity i = √-1 was developed to be the solution to the problem of solving quadratic equations which have the square-root of a negative number.

b. Expand (a + ib)⁵

(a + ib)⁵ = (a + ib)(a + ib)⁴ = (a + ib)(a + ib)²(a + ib)²

(a + ib)² = (a + ib)(a + ib) = a² + 2iab + (ib)² = a² + 2iab - b²

(a + ib)²(a + ib)² = (a² + 2iab - b²)(a² + 2iab - b²)

= a⁴ + 2ia³b - a²b² + 2ia³b + (2iab)² - 2iab³ - a²b² - 2iab³ + b⁴

= a⁴ + 2ia³b - a²b² + 2ia³b - 4a²b² - 2iab³ - a²b² - 2iab³ + b⁴

collecting like terms, we have

= a⁴ + 2ia³b + 2ia³b - a²b² - 4a²b² - a²b² - 2iab³ - 2iab³ + b⁴

= a⁴ + 4ia³b - 6a²b² - 4iab³ + b⁴

(a + ib)(a + ib)⁴ = (a + ib)(a⁴ + 4ia³b - 6a²b² - 4iab³ + b⁴)

= a⁵ + 4ia⁴b - 6a³b² - 4ia²b³ + ab⁴ + ia⁴b + 4i²a³b² - 6ia²b³ - 4i²ab⁴ + ib⁵

= a⁵ + 4ia⁴b - 6a³b² - 4ia²b³ + ab⁴ + ia⁴b - 4a³b² - 6ia²b³ + 4ab⁴ + ib⁵

collecting like terms, we have

= a⁵ + 4ia⁴b + ia⁴b - 6a³b² - 4a³b² - 4ia²b³ - 6ia²b³ + ab⁴ + 4ab⁴ + ib⁵

= a⁵ + 5ia⁴b - 10a³b² - 10ia²b³ + 5ab⁴ + ib⁵

So, (a + ib)⁵ = a⁵ + 5ia⁴b - 10a³b² - 10ia²b³ + 5ab⁴ + ib⁵

5 0

3 years ago

Which number is greatest?

user100 [1]

Answer:

$6.23 \times 10 {}^{12}$

Step-by-step explanation:

$6 .23\times 10 {}^{12}$

$6.23 \times 1000000000000 \\ 6230000000000$

7 0

3 years ago

Read 2 more answers

you want to mail a gift that is in the shape of a rectangular prism with the dimensions 25 cm by 32 CM by 40 cm .what is the min

Mkey [24]

Check the picture below.

notice, the gift box is just 6 rectangles stacked up to each other at the edges,

left and right, two rectangles of 32x40

top and bottom, two rectangles of 25x32

front and back, two rectangles of 25x40

so, just get the area of all 6 rectangles, add them up, and that's the "surface area" of the rectangular prism, and that's how much paper will be needed to cover it.

6 0

3 years ago