All categories

3 years ago

A copy machine makes 28 copies per min. How long does it take to make 119 copies?

Mathematics

2 answers:

LiRa [457]3 years ago

8 0

Answer:

4 minutes and 15 seconds

Step-by-step explanation:

119/28 = 4.25 (minutes)

.25 of a minute is 15 seconds, so the answer is 4 minutes and 15 seconds

andreev551 [17]3 years ago

6 0

Simply divide 119 per 28. The answer is 4 minutes and 15 seconds

You might be interested in

Please please please please helppppp

Marizza181 [45]

For question 3. A
4. A
5. B

6 0

3 years ago

Read 2 more answers

5x + 4 = 9 + 5(x - 1)

Wittaler [7]

Answer:

All real numbers are solutions!

Step-by-step explanation:

Let's solve your equation step-by-step.

5x+4=9+5(x−1)

Step 1: Simplify both sides of the equation.

5x+4=9+5(x−1)

5x+4=9+(5)(x)+(5)(−1)(Distribute)

5x+4=9+5x+−5

5x+4=(5x)+(9+−5)(Combine Like Terms)

5x+4=5x+4

Step 2: Subtract 5x from both sides.

5x+4−5x=5x+4−5x

4=4

Step 3: Subtract 4 from both sides.

4−4=4−4

0=0

4 0

3 years ago

6(3g2-9)<br><br> What is the answer to this question

Anika [276]

Answer: =18g^2−54

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

ANSWER ASAP PLEASE & SHOW UR WORK!!!

Lina20 [59]

Answer:

$x_1=\mathbf{i}\sqrt{6},\ x_2=-\mathbf{i}\sqrt{6},\ x_3=\sqrt{3},\ x_4=-\sqrt{3}$

Step-by-step explanation:

<u>Biquadratic Equations</u>

Solve:

$x^4 + 3x^2 - 18 = 0$

The biquadratic equations are equations of degree 4 without the terms of degree 1 and 3.

Solving such equations requires to express the equation as a second-degree equation with $x^2$ as the variable.

Rewriting the equation:

$(x^2)^2 + 3(x^2) - 18 = 0$

The quadratic equation can be factored as:

$(x^2+6)(x^2-3)=0$

It leads to two equations:

$x^2+6=0$

$x^2-3=0$

The first equation has imaginary roots. Solving for x:

$x^2=-6$

$x=\pm\sqrt{-6}$

$x_1=\mathbf{i}\sqrt{6}$

$x_2=-\mathbf{i}\sqrt{6}$

Where

$\mathbf{i}=\sqrt{-1}$

The second equation has two real roots:

$x^2-3=0$

$x^2=3$

$x=\pm\sqrt{3}$

$x_3=\sqrt{3}$

$x_4=-\sqrt{3}$

The roots are:

$\mathbf{x_1=\mathbf{i}\sqrt{6},\ x_2=-\mathbf{i}\sqrt{6},\ x_3=\sqrt{3},\ x_4=-\sqrt{3}}$

3 0

3 years ago

Which of the following is the solution to the inequality -6(4-x)<=-4(x+1)

alexandr1967 [171]

Answer:

first question huh

Step-by-step explanation:

7 0

4 years ago