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Oksanka [162]
3 years ago
5

maria bought 7 boxes. a week later half of all her boxes were destroyed in a fire. there are now only 22 boxes left. with how ma

ny did she start
Mathematics
2 answers:
VashaNatasha [74]3 years ago
8 0

Answer:

29

Step-by-step explanation:

x=22+7

x=29

timurjin [86]3 years ago
6 0
29 is the answer pretty sure
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Solve equation (n-1)(n+6)(n+5)=0
Vika [28.1K]
Answer:
1, -6 and -5 

Explanation:
To solve the equation means to get the values of n which satisfy the given equation.
The equation given is:
(n-1) (n+6) (n+5) = 0
This equation will be true if any of the terms (brackets) is equal to zero.
This means that:
either n-1 = 0 .............> n = 1
or n + 6 = 0 ................> n = -6
or n + 5 = 0 ................> n = -5

Hope this helps :)
5 0
3 years ago
Read 2 more answers
Fill in the missing number to name a fraction <br> equivalent to 6/8
Nataly [62]
3/4 would be a fraction, equivalent to 6/8.
4 0
3 years ago
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Review the problem below. Determine when the Associative, Commutative, and Additive Inverse properties are used and which operat
solmaris [256]

Answer:

christopher columbus

Step-by-step explanation:

4 0
2 years ago
The n term of a geometric sequence is denoted by Tn and the sum of the first n terms is denoted by Sn.Given T6-T4=5/2 and S5-S3=
Leno4ka [110]
1 step: S_{5}=T_{1}+T_{2}+T_{3}+T_{4}+T_{5}, S_{3}=T_{1}+T_{2}+T_{3}, then
 S_{5}-S_{3}=T_{4}+T_{5}=5.

2 step: T_{n}=T_{1}*q^{n-1}, then 
T_{6}=T_{1}*q^{5}
T_{5}=T_{1}*q^{4}
T_{4}=T_{1}*q^{3}
T_{3}=T_{1}*q^{2}
and \left \{ {{T_{6}-T_{4}= \frac{5}{2} } \atop {T_{5}+T_{4}=5}} \right. will have form \left \{ {{T_1*q^{5}-T_{1}*q^{3}= \frac{5}{2} } \atop {T_{1}*q^{4}+T_{1}*q^{3}=5} \right..

3 step: Solve this system  \left \{ {{T_1*q^{3}*(q^{2}-1)= \frac{5}{2} } \atop {T_{1}*q^{3}*(q+1)=5} \right. and dividing first equation on second we obtain \frac{q^{2}-1}{q+1}= \frac{ \frac{5}{2} }{5}. So, \frac{(q-1)(q+1)}{q+1} = \frac{1}{2} and q-1= \frac{1}{2}, q= \frac{3}{2} - the common ratio.

4 step: Insert q= \frac{3}{2}into equation T_{1}*q^{3}*(q+1)=5 and obtain T_{1}* \frac{27}{8}*( \frac{3}{2}+1 ) =5, from where T_{1}= \frac{16}{27}.




5 0
3 years ago
Triangle DEF is isosceles, where . Angle FDE is bisected by segment DG, creating angle GDE with a measure of 29°. What is the me
schepotkina [342]
Isosceles - two sides equal 

2 angels the same 
 
29 + 29 = 58 

180 - 58 = 122

122 = DFE 
5 0
3 years ago
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