Answer:
B, C and F
Step-by-step explanation:
Given
f(x) = ![\frac{7}{2x(x+3)(x-9)}](https://tex.z-dn.net/?f=%5Cfrac%7B7%7D%7B2x%28x%2B3%29%28x-9%29%7D)
The denominator of f(x) cannot be zero as this would make f(x) undefined.
Equating the denominator to zero and solving gives the values that x cannot be and if the numerator is non zero for these values then they are vertical asymptotes.
solve
2x(x + 3)(x - 9) = 0
Equate each factor to zero and solve for x
2x = 0 ⇒ x = 0 → C
x + 3 = 0 ⇒ x = - 3 → B
x - 9 = 0 ⇒ x = 9 → F
XX=-3+3√2 and c=-3-3√2 ....
Hope this helps you
Answer:
The equation of the Parallel line passes through the point (-1,4) is
y = -5 x -1
Step-by-step explanation:
<u><em>Explanation</em></u>:-
Given the equation of the line y = -5 x + 2
Given point (-1 , 4 )
The equation of the parallel line of a given line is 5x + y +k=0 ...(i)
The equation (i) passes through the point (-1,4)
5(-1)+4+k=0
-5 +4 +k =0
-1 + k = 0
k = 1
<em>The equation of the Parallel line passes through the point (-1,4) is </em>
<em> y = -5 x -1</em>