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Ilya [14]
3 years ago
7

Write an integer to describe the situation AND explain the meaning of zero. RISING 7 DEGREES

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
5 0
The answer is +7 I assume
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How do you solve this
sergeinik [125]
The square has sides of length s.
The rectange has 2 sides of s - 6 and 2 sides of s + 1
Perimeter is all the sides added up.
(s - 6) + (s - 6) + (s + 1) + (s + 1)
4s - 10
The answer is D. 4s - 10
6 0
3 years ago
Drag the correct steps into order to evaluate t + 8 • 4 for t = 2.
IceJOKER [234]

t + 8 x 4

2 + 8 x 4

2 + 32

34

7 0
3 years ago
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If the volume for 3-D polyhedra A is 200 cm3 and the volume for 3-D polyhedral B is 800 cm3, how many times bigger is the volume
Ann [662]
We're literally just comparing 200 to 800 here.
800 is 4× bigger than 200, of course.
To put that in a percent...
Well, 1 = 100%. (it's a whole)
So 4 = 400%
8 0
4 years ago
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CAN SOMEONE HELP ME WITH IS PLEAS AND THANK YOU.
Firlakuza [10]
Hi! so here, just multiply the tops and bottoms. once you have one fraction, find the greatest common factor, and divide top and bottom by that!! hope you do well!
7 0
3 years ago
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If a right triangle's hypotenuse is 17 units long, and one of its legs is 15 units long, how long is the other leg?
Vesna [10]

Answer:

8 units

Step-by-step explanation:

Hello!

So, there's a formula we can apply to right-angled triangles: Pythagorean's theorem. It states that  c = \sqrt{{a}^2 + b^{2} }, where <em>c</em> is the hypotenuse and <em>a</em> and <em>b </em>are the legs of the triangle.

So, from the problem,  if <em>c </em>= 17 and <em>a </em> = 15, then, we're solving for <em>b</em>. So we'll rewrite the theorem to solve for <em>b</em>.

{c}^2 = {a}^2+{b}^2\\{c}^2-{a}^2={b}^2\\{b} = \sqrt{{c}^2-{a}^2}

Okay, so now we have isolated the theorem for <em>b. Let's </em>plug in our values for <em>c </em>and <em>a</em>.

b = \sqrt{{17}^2-{15}^2}\\b = \sqrt{289-225}\\b = \sqrt{64}\\b = 8

So, using the theorem, we found <em>b</em> = 8. To check our work, let's plug in <em>b</em> and <em>a</em> and solve for <em>c.</em>

<em />c = \sqrt{{a}^2+{b}^2}}\\c = \sqrt{{15}^2+{8}^2}\\c = \sqrt{225+64}\\c = \sqrt{289}\\c = 17\\<em />

So, we got our hypotenuse to equal 17 units, which is correct! So, our <em>b</em> is correct too. Awesome

7 0
3 years ago
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