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deff fn [24]
3 years ago
7

My cats thoughts while she is just laying there with her face in my clothes:

Mathematics
2 answers:
nata0808 [166]3 years ago
7 0

Answer:

ADORABLE!!

Step-by-step explanation:

lina2011 [118]3 years ago
6 0

Answer:

lol true thats a fact

You might be interested in
every prime number greater than 10 has a digit in the ones place that is included in which set of numbers below?
stich3 [128]
So we can start with the full of possibilities and eliminate them one by one.

The full set is {0,1,2,3,4,5,6,7,8,9}.

Now we know that any prime greater than 2 is odd as otherwise it would have 2 as a factor, so we can eliminate all of these digits that would be an even number, leaving:

{1,3,5,7,9}

We also know that any prime greater than 5 cannot be a multiple of 5 and that all numbers with 5 in the digits are a multiple of 5, so we can eliminate 5.

{1,3,7,9}

We know that 11,13,17 and 19 are all primes, so we cannot eliminate any more of these, leaving the set:

{1,3,7,9} as our answer.
8 0
3 years ago
In the adjoining figure , APB and AQC are equilateral triangles. Prove that PC = BQ. ( Hint : <img src="https://tex.z-dn.net/?f=
just olya [345]

Answer:

See Below.

Step-by-step explanation:

Statements:                                                           Reasons:

\displaystyle 1)\text{ } \Delta APB \text{ and } \Delta AQC \text{ are equilateral triangles}      Given

\displaystyle 2) \text{ } m \angle PAB = 60                                                     Definition of equilateral.

3)\text{ } m \angle QAC = 60                                                     Definition of equilateral.

4)\text{ } m\angle PAB = m\angle QAC                                          Substitution

5)\text{ } m\angle PAC=m\angle PAB+m\angle BAC                       Angle Addition

\displaystyle 6)\text{ } m\angle QAB=m\angle QAC+m\angle BAC                       Angle Addition

7)\text{ } m\angle QAB=m\angle PAB+m\angle BAC                       Substitution

\displaystyle 8)\text{ } m\angle PAC=m\angle QAB                                         Substitution

9)\text{ } PA=BA                                                          Definition of equilateral

10)\text{ } AC=AQ                                                        Definition of equilateral

\displaystyle 11)\text{ } \Delta PAC \cong \Delta BAQ                                            Side-Angle-Side Congruence*

\displaystyle 12)\text{ } PC=BQ                                                        CPCTC

* SAS Congruence:

PA = BA

∠PAC = ∠QAB

AC = AQ

6 0
2 years ago
Read 2 more answers
0.8752x 78.56<br>3<br>0.00429 X 0.01​
Brums [2.3K]

Answer:

0.00294973268304

Step-by-step explanation:

8 0
2 years ago
Which of the following is NOT true? Question 19 options: (3x2y5)3=27x6y15 (1000x12y20z−3)0=1 52‾‾√3=523 42×43= 165
bixtya [17]

Answer:


Step-by-step explanation:

Lets try to simplify each to check which one is incorrect so it will be NOT true

first one is :

distribute the exponent so :

(3x^2y^5)^3 =3^3x^{2*3}y^{5*3}

27x^6y^{15} CORRECT

Second one is :

(1000x^{12}y^{20}z^{-30})^{0} =1

CORRECT because anything raised to exponent 0 is 1 .

Last one is :

4^2 *4^3 = 4^{2+3}\\=4^{6}\\=(4)^{2*3}\\=16^{3}

so Last is<em> INCORRECT</em>



5 0
3 years ago
I need help with this math problem.
DiKsa [7]

Answer:Multiply 410,000 with 26:)

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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