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3 years ago

15

Celina built a model of a triangular pyramid. The model's height is shown in the diagram.

2 answers:

brilliants [131]3 years ago

6 0

Answer: 12.85

Step-by-step explanation:

8_murik_8 [283]3 years ago

4 0

The answer is most likely 12.85

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F(x)=3x when x= -2,0,5

ololo11 [35]

Answer:

F(x)=3x when x= -2,0,5

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3 years ago

6% of what number is 24

Flura [38]

Answer:

4 i think, sorry if incorrect

Step-by-step explanation:

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3 years ago

Mr. peter travels 130 miles in 2 hours. at this rate, how many miles will he travel in 30 minutes?

enyata [817]

Alright so basically what you have to do here is realize that 130 miles is 2 hours, so if you divide by 2, you’ll have 65 miles in one hour ,, so 6mph, and if you divide again by two, you have 32.5 miles ,, therefore he travels 32.5 miles in 30 minutes

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3 years ago

You get paid $12/hr and earned $36, how many hours did you work?

Montano1993 [528]

Answer:

3 hours

Step-by-step explanation:

36 divided by 12 equals 3

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2 years ago

The difference between the two roots of the equation 3x^2+10x+c=0 is 4 2/3 . Find the solutions for the equation.

andrezito [222]

Answer:

Given the equation: $3x^2+10x+c =0$

A quadratic equation is in the form: $ax^2+bx+c = 0$ where a, b ,c are the coefficient and a≠0 then the solution is given by :

$x_{1,2} = \frac{-b\pm \sqrt{b^2-4ac}}{2a}$ ......[1]

On comparing with given equation we get;

a =3 , b = 10

then, substitute these in equation [1] to solve for c;

$x_{1,2} = \frac{-10\pm \sqrt{10^2-4\cdot 3 \cdot c}}{2 \cdot 3}$

Simplify:

$x_{1,2} = \frac{-10\pm \sqrt{100- 12c}}{6}$

Also, it is given that the difference of two roots of the given equation is $4\frac{2}{3} = \frac{14}{3}$

i.e,

$x_1 -x_2 = \frac{14}{3}$

Here,

$x_1 = \frac{-10 + \sqrt{100- 12c}}{6}$ , ......[2]

$x_2= \frac{-10 - \sqrt{100- 12c}}{6}$ .....[3]

then;

$\frac{-10 + \sqrt{100- 12c}}{6} - (\frac{-10 + \sqrt{100- 12c}}{6}) = \frac{14}{3}$

simplify:

$\frac{2 \sqrt{100- 12c} }{6} = \frac{14}{3}$

or

$\sqrt{100- 12c} = 14$

Squaring both sides we get;

$100-12c = 196$

Subtract 100 from both sides, we get

$100-12c -100= 196-100$

Simplify:

-12c = -96

Divide both sides by -12 we get;

c = 8

Substitute the value of c in equation [2] and [3]; to solve $x_1 , x_2$

$x_1 = \frac{-10 + \sqrt{100- 12\cdot 8}}{6}$

or

$x_1 = \frac{-10 + \sqrt{100- 96}}{6}$ or

$x_1 = \frac{-10 + \sqrt{4}}{6}$

Simplify:

$x_1 = \frac{-4}{3}$

Now, to solve for $x_2$ ;

$x_2 = \frac{-10 - \sqrt{100- 12\cdot 8}}{6}$

or

$x_2 = \frac{-10 - \sqrt{100- 96}}{6}$ or

$x_2 = \frac{-10 - \sqrt{4}}{6}$

Simplify:

$x_2 = -2$

therefore, the solution for the given equation is: $-\frac{4}{3}$ and -2.

3 0

3 years ago