All categories

3 years ago

There are 3 teaspoons in 1 tablespoon. How many teaspoons are there in 6 tablespoons?

Mathematics

1 answer:

Nezavi [6.7K]3 years ago

6 0

Answer:

Step-by-step explanation:

we can solve this as a ratio, from teaspoons to tablespoon is 3:1. if the tablespoon is 6 then the ratio becomes ?:6. Since we multiplied 1 by 6 we have to multiply 3 by 6 making the ratio 18:6.

You might be interested in

Use the Euclidean Algorithm to demonstrate that 621 and 82 are relatively prime to each other. Explain.

8090 [49]

Answer:

621 and 82 are relatively prime.

Step-by-step explanation:

Two integers are relatively prime (or coprime) if there is no integer greater than one that divides them both (that is, their greatest common divisor is one).

The greatest common divisor of two integers a and b is the largest integer that divides them both.

The Euclidean algorithm is an efficient method for computing the greatest common divisor of two integers, without explicitly factoring the two integers.

The Euclidean algorithm solves the problem:

Given integers a, b find $d=gcd(a,b)$

The Euclidean algorithm provides a fast way to determine d without knowing the prime factors of a or b. Here is an outline of the steps:

Let $a=x$ , $b=y$
Given x, y, use the division algorithm to write $x=yq+r, \quad 0\leq r\leq |y|$ .
If r = 0, stop and output y; this is the gcd of a, b.
If $r \neq 0$ , replace (x, y) by (y, r). Go to step 2.

The division algorithm is an algorithm in which given 2 integers N and D, it computes their quotient Q and remainder R.

Let's say we have to divide N (dividend) by D (divisor). We will take the following steps:

Step 1: Subtract D from N repeatedly until we get a result that lies between 0 (inclusive) and D (exclusive) and is the smallest non-negative number obtained by repeated subtraction.

Step 2: The resulting number is known as the remainder R, and the number of times that D is subtracted is called the quotient Q.

Applying the above steps,

$621-82=539\\539-82=457\\457-82=375\\375-82=293\\293-82=211\\211-82=129\\129-82=47\\\\621=82\cdot7+47$

$621 = 82\cdot 7 + 47\\ 82 = 47\cdot 1 + 35\\ 47 = 35\cdot1 + 12\\ 35 = 12\cdot2 + 11\\ 12 = 11\cdot1 + 1\\ 11 = 1\cdot11 + 0$

The gcd(621, 82) is 1. Therefore, 621 and 82 are relatively prime.

5 0

3 years ago

At what value of x does the graph of the following function F(x) have a

Free_Kalibri [48]

Answer:

Step-by-step explanation:

Given

f(x) = $\frac{1}{x+2}$

The denominator cannot be zero as this would make f(x) undefined.

Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non zero for this value then it is a vertical asymptote.

x + 2 = 0 ⇒ x = - 2

The equation of the vertical asymptote is x = - 2

6 0

3 years ago

Dejamos caer un objeto desde lo alto de una torre y medimos el tiempo que tarda en llegar al suelo , que resulta ser de 2,4 s (

Artyom0805 [142]

Answer:

Usando movimiento vertical de los cuerpos, la altura de la torre es:

h = 28,224 m

Step-by-step explanation:

Si dejamos caer el objeto, su velocidad inicial es cero: Vo=0 m/s

Tiempo que tarda en llegar al suelo: t=2,4 s

Altura de la torre: h=?

La altura de la torre es la distancia que recorre el objeto desde que se deja caer hasta que llega al suelo, entonces podemos usar la formula de distancia:

h = d = Vo t +/- a t^2/2

La aceleracion del cuerpo es la que ejerce la gravedad porque es caida libre, y es positiva porque el cuerpo va en la misma direccion que la aceleracion de la gravedad (hacia abajo):

h = Vo t + g t^2/2

Tomando la aceleracion de la gravedad como:

g=9,8 m/s^2

Y reemplazando los valores conocidos en la formula:

h = (0 m/s) (2,4 s) + (9,8 m/s^2) (2,4 s)^2 / 2

h= 0 m + (9,8 m/s^2) (5,76 s^2) / 2

h = 56,448 m / 2

h= 28,224 m

La altura de la torre es 28,224 m

6 0

3 years ago

Read 2 more answers

A simulated exercise gave n = 20 observations on escape time (sec) for oil workers, from which the sample mean and sample standa

mr Goodwill [35]

Answer:

Reject the null hypothesis, there is significant evidence that true average escape time exceeds 6 min.

Step-by-step explanation:

In this case we need to test whether the data contradict the prior belief that the true average escape time for oil workers would be at most 6 min or 360 seconds.

The information provided is:

$n=20\\\bar x=370.42\\s=25.74\\\alpha =0.05$