Answer:
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Step-by-step explanation:
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Let Fn be the number of ways of arranging such flagpole with the given conditions.
When arranging a flagpole of n feet high, consider the following cases
If the last flag used is a red flag, then the other flags are n-1 foot high, so they can be seen as arranged on a smaller flagpole of n-1 feet high, which can be done in Fn-1 ways.
Similarly, If the last flag used is a gold flag, then the other flags can be seen as arranged on a smaller flagpole of n-1 feet high. This can be done in Fn-1 ways.
If the last flag used is green, the other flags are n-2 feet high, so the flagpole can be arranged in Fn-2 ways.
Using the sum rule, we obtain that Fn = 2Fn-1 + Fn-2 for all n≥3. Listing all the combinations of flags, the initial conditions are F1 = 2 and F2 = 3.
To Learn more about similar flagpole questions:
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Answer:
68 square units
Step-by-step explanation:
The shape in the graph is a trapezoid. The two vertical sides are the parallel bases. The bottom horizontal side is the height.
A = (b1 + b2)h/2
A = (10 + 7)(8)/2
A = 68
Answer: 68 square units
Answer:
I need Help on this one too.
Step-by-step explanation:
please help