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ivolga24 [154]
3 years ago
10

Simplify the expression. ( 5 x 2 − 3 x ) − ( 5 x 2 − 3 x + 1 )

Mathematics
2 answers:
vampirchik [111]3 years ago
7 0

Answer:

Let's simplify step-by-step.

5x2−3x−(5x2−3x+1)

Distribute the Negative Sign:

=5x2−3x+−1(5x2−3x+1)

=5x2+−3x+−1(5x2)+−1(−3x)+(−1)(1)

=5x2+−3x+−5x2+3x+−1

Combine Like Terms:

=5x2+−3x+−5x2+3x+−1

=(5x2+−5x2)+(−3x+3x)+(−1)

=−1

Step-by-step explanation:

Show your work

iren [92.7K]3 years ago
6 0

Answer:

-1

Step-by-step explanation:

Following PEMDAS The answer equals to -1

<u>*plssss make me brainlist*</u>

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Show that a vector
Shtirlitz [24]

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 u = |u|(cos∝+cosβ+cosγ)

Step-by-step explanation:

<u>Explanation</u>

<u>Proof:-</u>

Given a vector  u = x₁ i + y₁j +z₁k

let O X, OY, O Z be the positive co-ordinate axes

P(x₁,y₁,z₁) be any point in the space

Let OP makes angles α,β,γ with co-ordinate axes OX , OY ,OZ .

The angle α,β,γ are known as direction angles and cosine of the angle

l =cosα , m= cosβ , n=cosγ

The perpendicular PA,PB,PC are drawn co-ordinate axes OX,OY,OZ respecctively

InΔOAP , ∠A =90° , cos∝ =\frac{x}{r}

                                 x₁ = rcos∝

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Given   u = x₁ i + y₁j +z₁k

      |u| = \sqrt{(x_{1})^{2} +(x_{2} )^{2} +(x_{3} )^{2}  }

Therefore  u = x₁ i + y₁j +z₁k

               u = |u|(cos∝+cosβ+cosγ)

         

​

6 0
3 years ago
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