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Kruka [31]
3 years ago
15

Model of how to find quotient 2.4 divided by 3

Mathematics
1 answer:
irga5000 [103]3 years ago
5 0
2.4/3. 3 goes into 2 0 times. 0 *3 is 0. 2-0 is 2. Bring down the four. 3 goes into 24 8 times. Bring the decimal directly above where it is above the bar. The answer is 0.8. (Sorry there are no pics).
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The distance d, in centimeters, that a diving board bends below its resting position when you stand at its end is dependent on y
kaheart [24]

Answer:

d(1) = -3 and d(2)= -28

Step-by-step explanation:

Given that the distance d, in centimeters, that a diving board bends below its resting position when you stand at its end is dependent on your distance x, in meters, from the stabilized point

d(x)=-4x^3+x^2

For finding out the distances for x=1 and x=2

let us substitute 1 and 2 for x

d(1) = -4(1^3)+1^2 = -3

d(2) = -4(2^3)+2^2 \\= -28

d(1) = -3 and d(2)= -28

3 0
3 years ago
Which expressions are equivalent to 2 (a + 3b)?
VARVARA [1.3K]

Answer:

A & B

Step-by-step explanation:

A is spot-on because of the use of distributive property. B by the use of like terms.

8 0
3 years ago
Which ordered pair is the best estimate for the
k0ka [10]
Given the pair of simultaneous equation:
y=-2/5x-2
y=5x+1
To evaluate the solution of the system of equation from the graph, we obtain the point at which the two linear equations have intersected. taking the values of x and y from the point of intersection that will be the solution of the system of linear equations. 
In our case the straight lines have intersected at the point (-0.5, -1.75). This implies that:
x=-0.5
y=-1.75
hence the answer is a] (-0.5, -1.75)
3 0
3 years ago
Cscx/secx = cotx<br><br> Verify with steps please :)
Dovator [93]
Csc(x) = 1/sin(x)
sec(x) = 1/cos(x)
cot(x) = [1/sin(x)] / [1/cos(x)] 
cot(x) = 1/sin(x) * cos(x)/1
cot(x) = cos(x) / sin(x)
cot(x) = cot(x)
6 0
3 years ago
Find the vertices of the hyperbola. Enter the smallest coordinate first.
melisa1 [442]

Answer:

([-3], [0]), ([3], [0])

Step-by-step explanation:

The given equation of the hyperbola is presented as follows;

\dfrac{x^2}{9} - \dfrac{y^2}{49} = 1

The vertices of an hyperbola (of the form)  \dfrac{x^2}{a^2} - \dfrac{y^2}{b^2} = 1 are (± a, 0)

The given hyperbola can we presented in a similar form as follows;

\dfrac{x^2}{9} - \dfrac{y^2}{49} = \dfrac{x^2}{3^2} - \dfrac{y^2}{7^2} = 1

Therefore, by comparison, the vertices of the parabola are (± 3, 0), which gives;

The vertices of the parabola are ([-3], [0]), ([3], [0]).

4 0
3 years ago
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