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joja [24]
3 years ago
14

A vegetable garden and a surrounding as a shaped like a square that together a 11 ft wide. The path is 2 feet wide. If one bag o

f gravel covers 10 square feet, how many bags are needed to cover the path? Round your answer to the nearest tenth. NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW. ​

Mathematics
1 answer:
Alexxandr [17]3 years ago
7 0

Answer:

\displaystyle     4

Step-by-step explanation:

we are given that A vegetable garden and a surrounding as a shaped like a square that together a 11 ft wide. The path is 2 feet wide.since together the width of Vegetable garden and path is 11 ft, the width of the vegetables garden will be the difference between the total width and the width of path Thus,

\displaystyle  \rm W _{ garden} = 11 - 2

simplify substraction:

\displaystyle  \rm W _{ garden} = 9

recall that, every single side of a square is equal to each other therefore the the area of the garden will be

\displaystyle    {9}^{2}

simplify square:

\displaystyle    81

together the garden and path makes a square of every side length 11 ft saying that the area will be:

\displaystyle    {11}^{2}

simplify square:

\displaystyle    121

the area of path will be the difference between the total area and the garden area therefore,

\displaystyle    121 - 81

simplify addition:

\displaystyle    40

to figure out how many bags are needed to cover the path. we just need to divide the area of the path by the area of a bag of gravel and that yields:

\displaystyle     \frac{40}{10}

simplify division:

\displaystyle     \boxed{\rm4}

hence,

<u>4</u> bags are needed to cover the path.

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Answer:

100.53m² area of carpet is left after putting the table in place.

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3 years ago
The points plotted below are on the graph of a polynomial. Which of the following x-values best approximate roots of the polynom
Brrunno [24]

Answer:

(3/2, 0+), (-1, 0+)

Step-by-step explanation:

An exact "zero" of a polynomial is characterized by a point on the x-axis.  In this case the best approximation to that is the point (3/2, 0+); the next best approximation is (-1, 0+).  Note that neither of these two points actually lies on the x-axis, but that both are closer to the x-axis than are any of the other given points.

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3 years ago
Use the following unit fractions to express 180 miles per hour in feet per second
harina [27]

Answer:

264 ft/sec

Step-by-step explanation:

We need to use the conversion factors

5280 ft/ 1 mi, 60 min/ 1 hr , and 60 sec/1 min

180 miles         1 hour               1 min        5280 ft

----------------- * -----------------  * ------------ * ---------------

hour                60 minutes       60 sec      1 miles

The hours, minutes and miles cancel are we are left with ft/sec

180 *5280        ft

----------------- * -----------------  

60*60                 sec      

264 ft/sec

8 0
3 years ago
Read 2 more answers
Solve asdp'l;s r0985yuiyd u9e6n98og r7 t8er 9o r5top 9 trr uir
vova2212 [387]

Answer:

the answer is 40√3feet per second

Step-by-step explanation:

v=√16.√300

v= 4. 10√3

NB:10√3=√100 .√3=√100.3= √300

Hence v =40√3ft per second

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3 years ago
Find an equation of the sphere with center (2, −10, 3) and radius 5. $$25=(x−2)2+(y−(−10))2+(z−3)2 use an equation to describe i
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In the x,y plane, we have z=0 everywhere. So in the equation of the sphere, we have

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which is a circle centered at (2, -10, 0) of radius 4.

In the x,z plane, we have y=0, which gives

25=(x-2)^2+10^2+(z-3)^2\implies(x-2)^2+(z-3)^2=-75

But any squared real quantity is positive, so there is no intersection between the sphere and this plane.

In the y,z plane, x=0, so

25=(-2)^2+(y+10)^2+(z-3)^2\implies(y+10)^2+(z-3)^2=21=(\sqrt{21})^2

which is a circle centered at (0, -10, 3) of radius \sqrt{21}.

3 0
4 years ago
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