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Jet001 [13]
3 years ago
14

Find an equation of the sphere with center (2, −10, 3) and radius 5. $$25=(x−2)2+(y−(−10))2+(z−3)2 use an equation to describe i

ts intersection with each of the coordinate planes. (if the sphere does not intersect with the plane, enter dne.)
Mathematics
1 answer:
lana66690 [7]3 years ago
3 0

In the x,y plane, we have z=0 everywhere. So in the equation of the sphere, we have

25=(x-2)^2+(y+10)^2+(-3)^2\implies(x-2)^2+(y+10)^2=16=4^2

which is a circle centered at (2, -10, 0) of radius 4.

In the x,z plane, we have y=0, which gives

25=(x-2)^2+10^2+(z-3)^2\implies(x-2)^2+(z-3)^2=-75

But any squared real quantity is positive, so there is no intersection between the sphere and this plane.

In the y,z plane, x=0, so

25=(-2)^2+(y+10)^2+(z-3)^2\implies(y+10)^2+(z-3)^2=21=(\sqrt{21})^2

which is a circle centered at (0, -10, 3) of radius \sqrt{21}.

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a water sprinkler sends water out in in a circle .how large is the watered area if the the watering Patten is 23 ft
Dennis_Churaev [7]
I'm guessing you're saying that the sprinkler is shooting out 23 ft of water.

This would be the same as the radius of a circle, and we're trying to find the area. Use the formula.

\sf A=\pi r^2

Plug in what we know:

\sf A=\pi (23^2)

\sf A=529\pi ft^2

This is what they could be looking for, an exact value. If they want an approximation, we can input 3.14 for Pi:

\sf A\approx 529(3.14)

\boxed{\sf A\approx 1661.06~ft^2}
3 0
3 years ago
5. A baseball player earns $2,913 for each game
ser-zykov [4K]

Answer:

471,906

Step-by-step explanation:

5 0
3 years ago
Solve x + 19 = 47.<br> Select one:<br><br> x = 893<br><br> x = 66<br><br> x = 28<br><br> x = 18
7nadin3 [17]

the answer is 28 hoped that helped

5 0
3 years ago
Read 2 more answers
Find the equation of the plane z = mx + ny + b which contains the points (0,0,6), (1,0,-3) and (0,2,5).
leonid [27]
The three points give you three equations, which you can solve by your favorite method.
.. 0m +0n +b = 6
.. 1m +0n +b = -3
.. 0m +2n +b = 5

(m, n, b) = (-9, -1/2, 6)
so the equation of the plane can be written as
.. z = -9x -1/2y +6

_____
In standard form, this would be
.. 18x +y +2z = 12

8 0
2 years ago
Un apostador pierde en su primer juego el 30% de su dinero, en el segundo juego pierde el 50% de lo que perdió; finalmente en el
sergiy2304 [10]

Responder:

26,62

Explicación paso a paso:

Sea x el dinero original que tenía el jugador:

si un jugador pierde en su primer juego el 30% de su dinero, la cantidad perdida será;

= 30/100 \ of \ x\\= 0.3x

Si en el segundo juego pierde el 50% de lo que perdió, entonces la cantidad perdida en el segundo juego será:

= 50/100 \ of \ 0.3x\\= 0.5 \times 0.3x\\= 0.15x

Si en el tercer juego pierde el 40% de todo lo que ha perdido, la cantidad perdida en el tercer juego será:

=\frac{40}{100} \ of \ (0.3x+0.15x) \\= 0.4(0.45x)\\= 0.2025x

Si la cantidad que le queda para seguir apostando es de 37 soles, entonces para calcular la cantidad original que tiene, sumaremos toda la cantidad perdida y la cantidad restante y equipararemos la cantidad original x como se muestra:

0,3x + 0,15x + 0,2025x + 37 = x

0,6525x + 37 = x

x-0,6525x = 37

0,3475x = 37

x = 37 / 0,3475

x = 106,48

La cantidad que tenía originalmente era de 106,48

75% de 106,48

= 75/100 * 106,48

= 0,75 * 106,48

= 79,86

Tomando la diferencia entre su monto original y su 75% será:

= 106.48-79.86\\= 26.62

3 0
2 years ago
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