Answer:
11 units
Step-by-step explanation:
To calculate CD use the distance formula
d = √ (x₂ - x₁ )² + (y₂ - y₁ )²
with (x₁, y₁ ) = C(- 4, 6) and (x₂, y₂ ) = D(- 4, - 5)
CD =
=
= =
= 11
PLS ANSWER Which number line represents the solutions to-2|x| =-6? o -8 8
1 answer:
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Answer:
m is 224°
Step-by-step explanation:
From the figure, we have;
The angle subtended at the circumference, by the arc mWXY, C = 112°
The angle subtended at the center = m
By circle theory, we have;
The angle subtended at the center = 2 × The angle subtended at the circumference
∴ m = 2 × 112° = 224°
m = 224°.
Answer:
Anything in the form x = pi+k*pi, for any integer k
These are not removable discontinuities.
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Explanation:
Recall that tan(x) = sin(x)/cos(x).
The discontinuities occur whenever cos(x) is equal to zero.
Solving cos(x) = 0 will yield the locations when we have discontinuities.
This all applies to tan(x), but we want to work with tan(x/2) instead.
Simply replace x with x/2 and solve for x like so
cos(x/2) = 0
x/2 = arccos(0)
x/2 = (pi/2) + 2pi*k or x/2 = (-pi/2) + 2pi*k
x = pi + 4pi*k or x = -pi + 4pi*k
Where k is any integer.
If we make a table of some example k values, then we'll find that we could get the following outputs:
- x = -3pi
- x = -pi
- x = pi
- x = 3pi
- x = 5pi
and so on. These are the odd multiples of pi.
So we can effectively condense those x equations into the single equation x = pi+k*pi
That equation is the same as x = (k+1)pi
The graph is below. It shows we have jump discontinuities. These are <u>not</u> removable discontinuities (since we're not removing a single point).
