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3 years ago

Please I need the correct answer please

Mathematics

1 answer:

Rzqust [24]3 years ago

8 0

(−1

2 )(n^3)+

1

2 n^2+4.6n+(−

1

2)(n^3)+

1

2 n^2+4.5n

−1

2 n^3+

2 n^2+4.6n+

−1

2 n^3+

2 n^2+4.5n

Combine Like Terms:

−1

2 n^3+

1

2 n^2+4.6n+

−1

2 n^3+

1

2 n^2+4.5n

=(−1

2 n^3+

−1

2 n^3)+(

1

2 n^2+

1

2 n^2)+(4.6n+4.5n)

=−n^3+n^2+9.1n

Answer:

=−n^3+n^2+9.1n

Everything underlined means its a fraction/divided hope this helps :D

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Convert these unlike fractions to equivalent like fractions and add them. You must use the LCD to get the answer correct. If pos

Gnoma [55]

The converted fractions are 3/12 and 5/12 and the sum is 2/3

<h3>How to convert the fractions?</h3>

From the question, the fractions are given as

1/4 and 5/12

The denominators of these fractions are

4 and 12

So. we start by calculating the LCD of the denominators

So, we have

4 = 2* 2

12 = 2 * 2 * 3

This gives

LCD = 2 * 2 * 3

Evaluate

LCD = 12

This means that the common denominator must be 12

So, we have

1/4 and 5/12

Multiply 1/4 by 3/3

This gives

3/12 and 5/12

When the fractions are added, we have

3/12 + 5/12 = (3 + 5)/12

Evaluate

3/12 + 5/12 = 8/12

Reduce fraction

3/12 + 5/12 = 2/3

Hence, the sum of the fractions is 2/3

Read more about fractions at

brainly.com/question/1622425

#SPJ1

8 0

1 year ago

Use the fundamental theorem of calculus to find the area of the region between the graph of the function x^5 + 8x^4 + 2x^2 + 5x

BaLLatris [955]

Answer:

The area of the region is 25,351 $units^2$ .

Step-by-step explanation:

The Fundamental Theorem of Calculus: if $f$ is a continuous function on $[a,b]$ , then

$\int_{a}^{b} f(x)dx = F(b) - F(a) = F(x) | {_a^b}$

where $F$ is an antiderivative of $f$ .

A function $F$ is an antiderivative of the function $f$ if

$F^{'}(x)=f(x)$

The theorem relates differential and integral calculus, and tells us how we can find the area under a curve using antidifferentiation.

To find the area of the region between the graph of the function $x^5 + 8x^4 + 2x^2 + 5x + 15$ and the x-axis on the interval [-6, 6] you must:

Apply the Fundamental Theorem of Calculus

$\int _{-6}^6(x^5+8x^4+2x^2+5x+15)dx$

$\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\\\\int _{-6}^6x^5dx+\int _{-6}^68x^4dx+\int _{-6}^62x^2dx+\int _{-6}^65xdx+\int _{-6}^615dx$

$\int _{-6}^6x^5dx=0\\\\\int _{-6}^68x^4dx=\frac{124416}{5}\\\\\int _{-6}^62x^2dx=288\\\\\int _{-6}^65xdx=0\\\\\int _{-6}^615dx=180\\\\0+\frac{124416}{5}+288+0+18\\\\\frac{126756}{5}\approx 25351.2$

3 0

3 years ago

Multiply 5x(x-2)(2x+1)

Aleks04 [339]

-20x is probably the correct answer

4 0

3 years ago

Can you help? photo is included

laiz [17]

Answer:

Step-by-step explanation:

f(x)=-4x+2

g(x)=x²+1

(gof)(x)=g(f(x))=g(-4x+2)=(-4x+2)²+2=16x²-16x+4+2=16x²-16x+6

(gof)(3)=16(3)²-16(3)+6=144-48+6=150-48=102

3 0

3 years ago

78 divided by 321.6 equals what show your work

AVprozaik [17]

Answer:

0.2425373

Step-by-step explanation:

78 divided by 321.6 equals to 0.2425373

7 0

3 years ago