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3 years ago

Could you help with this please? It would get my grade up and i'd get my stuff back.

Mathematics

2 answers:

prohojiy [21]3 years ago

6 0

Answer:

1. 20%??

2. 16.7 ??

3. 33% ??

Step-by-step explanation:

12345 [234]3 years ago

6 0

1- 3.8%
2- 84.37%
3- 78.66

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Given the figure as marked, identify the most specific type of quadrilateral.

kati45 [8]

Answer:

the answer is c. rectangle

8 0

3 years ago

Read 2 more answers

Solve this equation 3/8n=-1/4

lianna [129]

(3/8)*n = -1/4 // + -1/4

(3/8)*n-(-1/4) = 0

(3/8)*n+1/4 = 0

3/8*n+1/4 = 0 // - 1/4

3/8*n = -1/4 // : 3/8

n = -1/4/3/8

n = -2/3

n = -2/3

6 0

3 years ago

What is the slope of the line with an x-intercept value of -6 and a y-intercept value of 2

taurus [48]

Answer:

I think its 0 or undefined

Step-by-step explanation:

8 0

3 years ago

b. Find a 99% confidence interval for mean age of ICU patients using the facts that, in the sample, the mean is 57.55 years and

rjkz [21]

Answer:

99% of confidence intervals for mean age of ICU patients

(53.8920 , 61.2079)

Step-by-step explanation:

Explanation:-

Given sample mean $x^{-} = 57.55$

Given standard error is determined by

S.E = $\frac{S.D}{\sqrt{n} }$

Given data standard error = 1.42

99% of confidence intervals for mean is determined by

$(x^{-} - Z_{0.01} \frac{S.D}{\sqrt{n} } , x^{-} + Z_{0.01} \frac{S.D}{\sqrt{n} } )$

$Z_{\frac{\alpha }{2} } = Z_{\frac{0.01}{2} } = Z_{0.05} = 2.576$

$(x^{-} - 2.576 S.E , x^{-} + 2.576 S.E)$

$(57.55 - 2.576X 1.42 , 57.55+ 2.576 X1.42)$

(53.8920 , 61.2079)

Conclusion:-

99% of confidence intervals for mean is determined by

(53.8920 , 61.2079)

5 0

3 years ago

What is the equation of the line slope of 3 and passes through the point (-2, 3)?

elixir [45]

Answer:

$\large\boxed{y-3=3(x+2)}\qquad\text{point-slope form}\\\boxed{y=3x+9}\qquad\text{slope-intercept form}\\\boxed{3x-y=-9}\qquad\text{standard form}\\\boxed{3x-y+9=0}\qquad\text{general form}$

Step-by-step explanation:

The point-slope form of an equation of a line:

$y-y_1=m(x-x_1)$

We have the slope m = 3 and the point (-2, 3). Substitute:

$y-3=3(x-(-2))\\\\y-3=3(x+2)$

the point-slope form

$y-3=3(x+2)$ use the distributive property

$y-3=3x+6$ add 3 to both sides

$y=3x+9$

the slope-intercept form

$y=3x+9$ subtract 3x from both sides

$-3x+y=9$ change the signs

$3x-y=-9$

the standard form

$3x-y=-9$ add 9 to both sides

$3x-y+9=0$

the general form

8 0

4 years ago