First, we find the time spent accelerating:
s = ut + 1/2 at²; u = 0
10 = 1/2 5t²
t = 2 seconds
Velocity at point B:
v = u + at; u = 0, a = 5 m/s², t = 2 s
v = (5)(2) = 10 m/s
Now, the same velocity is at C so we find the time decelerating to 0 in CD
v = u + at, v = 0, u = 10 m/s, a = -4 m/s²
0 = 10 - 4t
t = 2.5 seconds
Total time = time(AB) + time(BC) + time(CD)
20 = 2 + time(BC) + 2.5
time(BC) = 15.5 seconds
Distance = velocity x time
BC = 10 x 15.5
= 155 m
Answer:
65,000
Step-by-step explanation:
6 1/2
= 13/2
= 6.5
6.5 * 10,000
= 65,000
Answer:
12 seconds.
Step-by-step explanation:
Let t represent time taken by code to sort an array of 24 elements.
We have been given that an algorithm takes 4 seconds to sort an array of 8 elements. We are asked to find the time it will take for same code to sort an array of 24 elements.
We will use proportions to solve our given problem.
Therefore, it will take 12 seconds for the same code to sort an array of 24 elements.
Answer:
h
Step-by-step explanation: h
Answer:
Step-by-step explanation:
5x - 9 ≤ 21
5x ≤ 30
x ≤ 6
