Answer:
Part 1) 
Part 2) 
Step-by-step explanation:
I will analyze two problems
see the attached figure to better understand the problem
Problem 1
The hypotenuse is the segment AB and the right angle is C
we know that
In the right triangle ABC
---> by SOH (opposite side divided by the hypotenuse)
substitute the given values

Remember that

substitute


Problem 2
The hypotenuse is the segment BC and the right angle is A
we know that
In the right triangle ABC
---> by TOA (opposite side divided by the adjacent side)
substitute the given values

Remember that

substitute


Answer:
nine hundred thirty-eight one hundred twenty thousandths
Step-by-step explanation:
Answer:
K1310.4
Step-by-step explanation:
Basic pay per hour = K7.20
Overtime pay during the week per hour = 1 1/2 * K7. 20 = K10.8
Weekends = 2 * K7.20 = K14.4
Basic hours per week = 70 hours
In a fortnight :
Basic hours = 70 * 2 = 140 hours :
Hence, Overtime during the week = (160 - 140) = 20 hours
Weekend hours = (4 +2) = 6 hours
Total earning :
(140 * 7.20) + (20 * 10.8) + (6 * 14.4)
1008 + 216 + 86.4
= K1310.4
I think it would be:
10, 12.5, 17, 19.5, 23
hope it helps
The possible outcomes for 1 HEAD and 3 TAILS are
HTTT
THTT
TTHT
TTTH
Assuming the coin is a fair coin, we have:
Probability of tossing head is 0.5
Probability of tossing tail is 0.5
Probability of tossing the coin four times for each outcome combination listed above is
HTTT = 0.5×0.5×0.5×0.5 = 0.0625
THTT = 0.5×0.5×0.5×0.5 = 0.0625
TTHT = 0.5×0.5×0.5×0.5 = 0.0625
TTTH = 0.5×0.5×0.5×0.5 = 0.0625
Hence, probability of getting three tails and one head from 4 tossing is
4×0.0625 = 0.25