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Setler [38]
3 years ago
5

What is the domain of \sqrt{4-6a}? PLS ANSWER SOON DUE TMRW

Mathematics
1 answer:
Igoryamba3 years ago
8 0

Answer:

(−∞,2/3],{a∣a≤2/3}

<h2>Step-by-step explanation:</h2>

math

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PLEASE HELP! I WILL MAKE YOU BRAINLIST!
Mice21 [21]

Answer: I think it is C

Step-by-step explanation: 32/4=8 so 1 cm = 8km

5 0
3 years ago
Cecilia is making cookies for her friends. The recipe, which makes 48 cookies, calls for 4 cups of flour and 1 1/3 cups of sugar
Vsevolod [243]

Answer:

2. Cecilia uses 3 cups of flour for 36 cookies

4. Cecilia is making 3/4 of the original recipe

Step-by-step explanation:

Recipe for 48 cookies

Flour = 4 cups

Sugar = 1 1/3 cups

Recipe for 36 cookies

48 cookies : 36 cookies

= 4 : 3

Flour used in 36 cookies = x cups

Flour used in 48 cookies = 4 cups

4 cups : x cups

4 : 3 = 4 : x

4/3 = 4/x

4*x = 3*4

4x = 12

x = 12/4

x = 3 cups

Sugar = 1 1/3 cups

Sugar used in 36 cookies = y cups

Sugar used in 48 cookies = 1 1/3 cups

4 : 3 = 1 1/3 : y

4/3 = 4/3 ÷ y

4/3 = 4/3 × 1/y

4/3 = 4/3y

4*3y = 3*3

12y = 9

y = 9/12

= 3/4

y = 3/4

The true statement are:

2. Cecilia uses 3 cups of flour for 36 cookies

4. Cecilia is making 3/4 of the original recipe

8 0
3 years ago
(a) How many integers from 1 through 1,000 are multiples of 2 or multiples of 9?
DENIUS [597]

Answer:

(a)There are 500 integers from 1 through 1,000 are multiples of 2.

There are 111 integers from 1 through 1,000 are multiples of 9.

(b)0.611

Step-by-step explanation:

Given the set of Integers from 1 through 1000

The least multiple of 2 is 2 and the highest multiple of 2 in the interval is 1000.

To determine the number of terms, we use the formula for the nth term of an Arithmetic Progression, since 2,4,6,... is an Arithmetic Progression,

where first term, a =2, common difference, d =2

Nth term of an A.P,

U_n= a+(n-1)d\\1000=2+2(n-1)\\1000=2+2n-2\\1000=2n\\n=500

  • There are 500 integers from 1 through 1,000 are multiples of 2.

Similarly,

Given the set of Integers from 1 through 1000

The least multiple of 9 is 9 and the highest multiple of 9 in the interval is 999.

To determine the number of terms, we use the formula for the nth term of an Arithmetic Progression, since 9,18,27,... is an Arithmetic Progression,

where first term, a =9, common difference, d =9

Nth term of an A.P,

U_n= a+(n-1)d\\999=9+9(n-1)\\999=9+9n-9\\999=9n\\n=111

  • There are 111 integers from 1 through 1,000 are multiples of 9.

(b)Probability that an integer selected at random is a multiple of 2 or a multiple of 9.

There are a total of 1000 numbers between from 1 through 1,000

n(S)=1000

n(Multiples of 2)=500

n(Multiples of 9)=111

Therefore:

P(\text{Multiples of 9}) \:OR\: P(\text{Multiples of 2})=\frac{111}{1000} + \frac{500}{1000} \\=\frac{611}{1000} \\=0.611

7 0
3 years ago
What Is the area of the trapezoid​
umka2103 [35]

18m

Step-by-step explanation:

5x3=15 +3 =18

5 0
3 years ago
I need help ON THIS PLS
Anit [1.1K]

Answer:

No, because the ratio of pay to hours is not the same for each pair of value.

8 0
3 years ago
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