Answer:
Honey, I don't know what you need help with. Nothing is linked.
Step-by-step explanation:
To solve this problem, let us first assign some
variables. Let us say that:
x = pigs
y = chickens
z = ducks
From the problem statement, we can formulate the
following equations:
1. y + z = 30 --->
only chicken and ducks have feathers
2. 4 x + 2 y + 2 z = 120 --->
pig has 4 feet, while chicken and duck has 2 each
3. 2 x + 2 y + 2 z = 90 --->
each animal has 2 eyes only
Rewriting equation 1 in terms of y:
y = 30 – z
Plugging this in equation 2:
4 x + 2 (30 – z) + 2 z = 120
4 x + 60 – 2z + 2z = 120
4 x = 120 – 60
4 x = 60
x = 15
From the given choices, only one choice has 15 pigs. Therefore
the answers are:
She has 15 pigs, 12 chickens, and 18 ducks.
5/54 this should be your answers hope this helps
5. The blue one is y >= 5x - 7
and green is y >= -0.65x + 3
6. y <= (4/5)x
y >= -(5/4)x
<span>y = 9/3 x - 5/3
3y = 9x - 5
9x - 3y = 5 ...<----this is standard form</span>
