Answer:
0=0
Step-by-step explanation:
Well, the linear equation can be expressed as y=ax+b in the solution of linear equations, there 3 main cases can be concluded as final lines. 1st case - the linear equation has no solution (for example, 0*x=5 has no solutions). 2nd case - the linear equation has one solution (for example 4*x=3 where the only one solution is x=0.75) and the 3rd case - the linear equation has infinite number of solutions (for example 0*x=0). So, in our case (3rd case) the last line can be concluded as 0=0.
The two consecutive odd integers are 57 & 59.
Answer:
30 each of 23% bars and 18 each of 79% bars
Step-by-step explanation:
If x is the number of 1 kg 23% copper bars, and y is the number of 1 kg 79% copper bars, then:
x + y = 48
0.23x + 0.79y = 0.44(48)
Substituting and solving:
0.23x + 0.79(48-x) = 0.44(48)
0.23x + 37.92 - 0.79x = 21.12
16.8 = 0.56x
x = 30
y = 48 - x
y = 18
You need 30 each of 23% bars and 18 each of 79% bars.
Answer:
D is not a supported statement
Step-by-step explanation:
Let take them one by one:
A: from table: 0.57; in statement: 0.5
0.57 > 0.5 so this is supported
B: from table: 0.2+0.16=0.36; in statement: 1/3=0.33,
0.36>0.33 so this is supported
C: 0.07 is the least, so this is supported
D: the table DOES NOT show number of students, but proportions. So statement '7 students' IS NOT supported
E: from table 0.20 overslept. 0.2 < 1/4=0.25, so this is supported
Answer:
4.1145
Step-by-step explanation:
You can use the following formula to solve this kind of problems,
So, let's start of with log4_(300). Since the question have already gave log4_(3) =0.7925 and log4_(5) =1.1610. It means that you have to split the 300 into the simplest form where almost all of the numbers are 3 and 5.
