Question

Use the graph and table to write the equation that describes the line graphed.

Answer 1

Answer:

I believe it is x−y+3=0.

Step-by-step explanation:

y= mx + b

The equation of a line is written as $\frac{y_{2-}{y_{1} } }{x_{2-}{x_{1} } }$, so if you plug in the numbers from the first two rows on the grid you get, $\frac{2-1}{-1--2}$ = $\frac{1}{1}$ = 1

The y- intercept is $b= y_{1}$-m·$x_{1}$, plug in the number and its, b=1-(1)·(-2)=3

Finally, the equation of the line can be written in the form y=mx+b.

y=x+3.

The equation of the line in the slope-intercept form is y=x+3.

The equation of the line in the point-slope form is y−1=1(x+2).

The general equation of the line is x−y+3=0.

Answer 2

Answer:

It’s D y=X+3

Step-by-step explanation: